The number 61241
61241 is a composite number with 4 divisors. Its prime factorisation is 47 × 1303. Divisors (4): 1, 47, 1303, 61241.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 61241: a semiprime: 47 × 1303, the product of two primes.
- 2
61241 is composite. Its prime factorisation is
- 3
The divisors add up to 62592; without 61241 itself that is 1351, so 61241 is deficient (1351 is less than 61241). Euler's totient φ(61241) = 59892 numbers up to 61241 share no factor with it.
- 4
The digits of 61241 add up to 14, and repeating that until one digit is left gives the digital root 5. The Collatz sequence (halve if even, else 3n+1) takes 86 steps to reach 1.
LaTeX source of the formulas on this page
\[ 61241 = 47 \times 1303 \]
61241 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 4 |
| Sum of divisors | 62592 |
| Euler totient φ(n) | 59892 |
| Square | 3750460081 |
| Cube | 229681925820521 |
| Square root | 247.469190 |
| Digit sum / digital root | 14 / 5 |
| Collatz steps to 1 | 86 |
| Scientific notation | 6.1241 × |
61241 in other forms
| Form | Value |
|---|---|
| In words | sixty-one thousand two hundred and forty-one |
| Binary (base 2) | 1110111100111001 |
| Octal (base 8) | 167471 |
| Hexadecimal (base 16) | EF39 |
| Base 3 | 10010000012 |
| As time | 61241 seconds = 17 h 0 min 41 s |
Is 61241 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 2) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 1) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 1) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 5) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 5) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 1) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 5) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 1) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 4) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 5) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 61241 a prime number?
No. 61241 = 47 × 1303, so it is divisible by 47.
What are the factors of 61241?
1, 47, 1303, 61241.
What is 61241 in binary?
1110111100111001 (hexadecimal EF39, octal 167471).
What is the square root of 61241?
About 247.4692.
Is 61241 divisible by 3?
No. Its digits add up to 14, which is not a multiple of 3.
What is special about the number 61241?
61241 is a semiprime: 47 × 1303, the product of two primes.