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The number 61097

61097 is a composite number with 4 divisors. Its prime factorisation is 107 × 571. Divisors (4): 1, 107, 571, 61097.

Number

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How to work it out

  1. 1

    What is special about 61097: a happy number: repeatedly adding the squares of its digits reaches 1; a semiprime: 107 × 571, the product of two primes.

  2. 2

    61097 is composite. Its prime factorisation is

    61097=107×57161097 = 107 \times 571
  3. 3

    The divisors add up to 61776; without 61097 itself that is 679, so 61097 is deficient (679 is less than 61097). Euler's totient φ(61097) = 60420 numbers up to 61097 share no factor with it.

  4. 4

    The digits of 61097 add up to 23, and repeating that until one digit is left gives the digital root 5. The Collatz sequence (halve if even, else 3n+1) takes 179 steps to reach 1.

LaTeX source of the formulas on this page
\[ 61097 = 107 \times 571 \]

61097 at a glance

PropertyValue
Typecomposite
Number of divisors4
Sum of divisors61776
Euler totient φ(n)60420
Square3732843409
Cube228065533759673
Square root247.178073
Digit sum / digital root23 / 5
Collatz steps to 1179
Scientific notation6.1097 × 10410^{4}

61097 in other forms

FormValue
In wordssixty-one thousand and ninety-seven
Binary (base 2)1110111010101001
Octal (base 8)167251
Hexadecimal (base 16)EEA9
Base 310002210212
As time61097 seconds = 16 h 58 min 17 s

Is 61097 divisible by 2 to 12?

DivisorAnswerRule
2No (remainder 1)A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8).
3No (remainder 2)A number is divisible by 3 if the digits add up to a multiple of 3.
4No (remainder 1)A number is divisible by 4 if the last two digits make a multiple of 4.
5No (remainder 2)A number is divisible by 5 if the last digit is 0 or 5.
6No (remainder 5)A number is divisible by 6 if it is divisible by both 2 and 3.
7No (remainder 1)A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7.
8No (remainder 1)A number is divisible by 8 if the last three digits make a multiple of 8.
9No (remainder 5)A number is divisible by 9 if the digits add up to a multiple of 9.
10No (remainder 7)A number is divisible by 10 if the last digit is 0.
11No (remainder 3)A number is divisible by 11 if the alternating sum of the digits is a multiple of 11.
12No (remainder 5)A number is divisible by 12 if it is divisible by both 3 and 4.

Questions

Is 61097 a prime number?

No. 61097 = 107 × 571, so it is divisible by 107.

What are the factors of 61097?

1, 107, 571, 61097.

What is 61097 in binary?

1110111010101001 (hexadecimal EEA9, octal 167251).

What is the square root of 61097?

About 247.1781.

Is 61097 divisible by 3?

No. Its digits add up to 23, which is not a multiple of 3.

What is special about the number 61097?

61097 is a happy number: repeatedly adding the squares of its digits reaches 1; a semiprime: 107 × 571, the product of two primes.

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