The number 60993
60993 is a composite number with 12 divisors. Its prime factorisation is × 251. Divisors (12): 1, 3, 9, 27, 81, 243, 251, 753, 2259, 6777, 20331, 60993.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 60993: a Harshad number: divisible by its digit sum 27.
- 2
60993 is composite. Its prime factorisation is
- 3
The divisors add up to 91728; without 60993 itself that is 30735, so 60993 is deficient (30735 is less than 60993). Euler's totient φ(60993) = 40500 numbers up to 60993 share no factor with it.
- 4
The digits of 60993 add up to 27, and repeating that until one digit is left gives the digital root 9. The Collatz sequence (halve if even, else 3n+1) takes 73 steps to reach 1.
LaTeX source of the formulas on this page
\[ 60993 = 3^{5} \times 251 \]60993 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 12 |
| Sum of divisors | 91728 |
| Euler totient φ(n) | 40500 |
| Square | 3720146049 |
| Cube | 226902867966657 |
| Square root | 246.967609 (= 9√753) |
| Digit sum / digital root | 27 / 9 |
| Collatz steps to 1 | 73 |
| Scientific notation | 6.0993 × |
60993 in other forms
| Form | Value |
|---|---|
| In words | sixty thousand nine hundred and ninety-three |
| Binary (base 2) | 1110111001000001 |
| Octal (base 8) | 167101 |
| Hexadecimal (base 16) | EE41 |
| Base 3 | 10002200000 |
| As time | 60993 seconds = 16 h 56 min 33 s |
Is 60993 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | Yes (60993 ÷ 3 = 20331) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 1) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 3) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 3) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 2) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 1) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | Yes (60993 ÷ 9 = 6777) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 3) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 9) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 9) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 60993 a prime number?
No. 60993 = × 251, so it is divisible by 3.
What are the factors of 60993?
1, 3, 9, 27, 81, 243, 251, 753, 2259, 6777, 20331, 60993.
What is 60993 in binary?
1110111001000001 (hexadecimal EE41, octal 167101).
What is the square root of 60993?
About 246.9676, exactly 9√753.
Is 60993 divisible by 3?
Yes. Its digits add up to 27, a multiple of 3.
What is special about the number 60993?
60993 is a Harshad number: divisible by its digit sum 27.