The number 60991
60991 is a composite number with 4 divisors. Its prime factorisation is 7 × 8713. Divisors (4): 1, 7, 8713, 60991.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 60991: a semiprime: 7 × 8713, the product of two primes.
- 2
60991 is composite. Its prime factorisation is
- 3
The divisors add up to 69712; without 60991 itself that is 8721, so 60991 is deficient (8721 is less than 60991). Euler's totient φ(60991) = 52272 numbers up to 60991 share no factor with it.
- 4
The digits of 60991 add up to 25, and repeating that until one digit is left gives the digital root 7. The Collatz sequence (halve if even, else 3n+1) takes 223 steps to reach 1.
LaTeX source of the formulas on this page
\[ 60991 = 7 \times 8713 \]
60991 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 4 |
| Sum of divisors | 69712 |
| Euler totient φ(n) | 52272 |
| Square | 3719902081 |
| Cube | 226880547822271 |
| Square root | 246.963560 |
| Digit sum / digital root | 25 / 7 |
| Collatz steps to 1 | 223 |
| Scientific notation | 6.0991 × |
60991 in other forms
| Form | Value |
|---|---|
| In words | sixty thousand nine hundred and ninety-one |
| Binary (base 2) | 1110111000111111 |
| Octal (base 8) | 167077 |
| Hexadecimal (base 16) | EE3F |
| Base 3 | 10002122221 |
| As time | 60991 seconds = 16 h 56 min 31 s |
Is 60991 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 1) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 3) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 1) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 1) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | Yes (60991 ÷ 7 = 8713) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 7) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 7) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 1) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 7) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 7) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 60991 a prime number?
No. 60991 = 7 × 8713, so it is divisible by 7.
What are the factors of 60991?
1, 7, 8713, 60991.
What is 60991 in binary?
1110111000111111 (hexadecimal EE3F, octal 167077).
What is the square root of 60991?
About 246.9636.
Is 60991 divisible by 3?
No. Its digits add up to 25, which is not a multiple of 3.
What is special about the number 60991?
60991 is a semiprime: 7 × 8713, the product of two primes.