WordGPT

The number 59985

59985 is a composite number with 24 divisors. Its prime factorisation is 323^{2} × 5 × 31 × 43. Divisors (24): 1, 3, 5, 9, 15, 31, 43, 45, 93, 129, 155, 215, 279, 387, 465, 645 … 59985.

Number

Pick any whole number from 1 to 100,000.

How to work it out

  1. 1

    59985 has no famous special property in the usual lists (prime, square, cube, triangular, Fibonacci, palindrome, perfect), but it is still a composite number.

  2. 2

    59985 is composite. Its prime factorisation is

    59985=32×5×31×4359985 = 3^{2} \times 5 \times 31 \times 43
  3. 3

    The divisors add up to 109824; without 59985 itself that is 49839, so 59985 is deficient (49839 is less than 59985). Euler's totient φ(59985) = 30240 numbers up to 59985 share no factor with it.

  4. 4

    The digits of 59985 add up to 36, and repeating that until one digit is left gives the digital root 9. The Collatz sequence (halve if even, else 3n+1) takes 65 steps to reach 1.

LaTeX source of the formulas on this page
\[ 59985 = 3^{2} \times 5 \times 31 \times 43 \]

59985 at a glance

PropertyValue
Typecomposite
Number of divisors24
Sum of divisors109824
Euler totient φ(n)30240
Square3598200225
Cube215838040496625
Square root244.918354 (= 3√6665)
Digit sum / digital root36 / 9
Collatz steps to 165
Scientific notation5.9985 × 10410^{4}

59985 in other forms

FormValue
In wordsfifty-nine thousand nine hundred and eighty-five
Binary (base 2)1110101001010001
Octal (base 8)165121
Hexadecimal (base 16)EA51
Base 310001021200
As time59985 seconds = 16 h 39 min 45 s

Is 59985 divisible by 2 to 12?

DivisorAnswerRule
2No (remainder 1)A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8).
3Yes (59985 ÷ 3 = 19995)A number is divisible by 3 if the digits add up to a multiple of 3.
4No (remainder 1)A number is divisible by 4 if the last two digits make a multiple of 4.
5Yes (59985 ÷ 5 = 11997)A number is divisible by 5 if the last digit is 0 or 5.
6No (remainder 3)A number is divisible by 6 if it is divisible by both 2 and 3.
7No (remainder 2)A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7.
8No (remainder 1)A number is divisible by 8 if the last three digits make a multiple of 8.
9Yes (59985 ÷ 9 = 6665)A number is divisible by 9 if the digits add up to a multiple of 9.
10No (remainder 5)A number is divisible by 10 if the last digit is 0.
11No (remainder 2)A number is divisible by 11 if the alternating sum of the digits is a multiple of 11.
12No (remainder 9)A number is divisible by 12 if it is divisible by both 3 and 4.

Questions

Is 59985 a prime number?

No. 59985 = 323^{2} × 5 × 31 × 43, so it is divisible by 3.

What are the factors of 59985?

1, 3, 5, 9, 15, 31, 43, 45, 93, 129, 155, 215, 279, 387, 465, 645, 1333, 1395, 1935, 3999, 6665, 11997, 19995, 59985.

What is 59985 in binary?

1110101001010001 (hexadecimal EA51, octal 165121).

What is the square root of 59985?

About 244.9184, exactly 3√6665.

Is 59985 divisible by 3?

Yes. Its digits add up to 36, a multiple of 3.

What is special about the number 59985?

It is a composite number with 24 divisors.

Find the next one

Nearby numbers

    59985: is it prime? Factors, square root, binary, Roman numeral | WordGPT