The number 59938
59938 is a composite number with 8 divisors. Its prime factorisation is 2 × 23 × 1303. Divisors (8): 1, 2, 23, 46, 1303, 2606, 29969, 59938.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
59938 has no famous special property in the usual lists (prime, square, cube, triangular, Fibonacci, palindrome, perfect), but it is still a composite number.
- 2
59938 is composite. Its prime factorisation is
- 3
The divisors add up to 93888; without 59938 itself that is 33950, so 59938 is deficient (33950 is less than 59938). Euler's totient φ(59938) = 28644 numbers up to 59938 share no factor with it.
- 4
The digits of 59938 add up to 34, and repeating that until one digit is left gives the digital root 7. The Collatz sequence (halve if even, else 3n+1) takes 166 steps to reach 1.
LaTeX source of the formulas on this page
\[ 59938 = 2 \times 23 \times 1303 \]
59938 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 8 |
| Sum of divisors | 93888 |
| Euler totient φ(n) | 28644 |
| Square | 3592563844 |
| Cube | 215331091681672 |
| Square root | 244.822385 |
| Digit sum / digital root | 34 / 7 |
| Collatz steps to 1 | 166 |
| Scientific notation | 5.9938 × |
59938 in other forms
| Form | Value |
|---|---|
| In words | fifty-nine thousand nine hundred and thirty-eight |
| Binary (base 2) | 1110101000100010 |
| Octal (base 8) | 165042 |
| Hexadecimal (base 16) | EA22 |
| Base 3 | 10001012221 |
| As time | 59938 seconds = 16 h 38 min 58 s |
Is 59938 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | Yes (59938 ÷ 2 = 29969) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 1) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 2) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 3) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 4) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 4) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 2) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 7) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 8) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 10) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 10) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 59938 a prime number?
No. 59938 = 2 × 23 × 1303, so it is divisible by 2.
What are the factors of 59938?
1, 2, 23, 46, 1303, 2606, 29969, 59938.
What is 59938 in binary?
1110101000100010 (hexadecimal EA22, octal 165042).
What is the square root of 59938?
About 244.8224.
Is 59938 divisible by 3?
No. Its digits add up to 34, which is not a multiple of 3.
What is special about the number 59938?
It is a composite number with 8 divisors.