The number 59887
59887 is the 6050th prime number. Its only divisors are 1 and 59887.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 59887: the 6050th prime number.
- 2
59887 is prime, so its only factors are 1 and 59887. It is the 6050th prime; the next prime is 59921 and the one before is 59879.
- 3
The divisors add up to 59888; without 59887 itself that is 1, so 59887 is deficient (1 is less than 59887). Euler's totient φ(59887) = 59886 numbers up to 59887 share no factor with it.
- 4
The digits of 59887 add up to 37, and repeating that until one digit is left gives the digital root 1. The Collatz sequence (halve if even, else 3n+1) takes 210 steps to reach 1.
59887 at a glance
| Property | Value |
|---|---|
| Type | prime |
| Number of divisors | 2 |
| Sum of divisors | 59888 |
| Euler totient φ(n) | 59886 |
| Square | 3586452769 |
| Cube | 214781896977103 |
| Square root | 244.718205 |
| Digit sum / digital root | 37 / 1 |
| Collatz steps to 1 | 210 |
| Scientific notation | 5.9887 × |
59887 in other forms
| Form | Value |
|---|---|
| In words | fifty-nine thousand eight hundred and eighty-seven |
| Binary (base 2) | 1110100111101111 |
| Octal (base 8) | 164757 |
| Hexadecimal (base 16) | E9EF |
| Base 3 | 10001011001 |
| As time | 59887 seconds = 16 h 38 min 7 s |
Is 59887 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 1) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 3) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 2) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 1) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 2) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 7) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 1) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 7) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 3) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 7) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 59887 a prime number?
Yes. 59887 is divisible only by 1 and itself.
What are the factors of 59887?
1, 59887.
What is 59887 in binary?
1110100111101111 (hexadecimal E9EF, octal 164757).
What is the square root of 59887?
About 244.7182.
Is 59887 divisible by 3?
No. Its digits add up to 37, which is not a multiple of 3.
What is special about the number 59887?
59887 is the 6050th prime number.