The number 59427
59427 is a composite number with 16 divisors. Its prime factorisation is × 31 × 71. Divisors (16): 1, 3, 9, 27, 31, 71, 93, 213, 279, 639, 837, 1917, 2201, 6603, 19809, 59427.
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How to work it out
- 1
What is special about 59427: a Harshad number: divisible by its digit sum 27.
- 2
59427 is composite. Its prime factorisation is
- 3
The divisors add up to 92160; without 59427 itself that is 32733, so 59427 is deficient (32733 is less than 59427). Euler's totient φ(59427) = 37800 numbers up to 59427 share no factor with it.
- 4
The digits of 59427 add up to 27, and repeating that until one digit is left gives the digital root 9. The Collatz sequence (halve if even, else 3n+1) takes 73 steps to reach 1.
LaTeX source of the formulas on this page
\[ 59427 = 3^{3} \times 31 \times 71 \]59427 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 16 |
| Sum of divisors | 92160 |
| Euler totient φ(n) | 37800 |
| Square | 3531568329 |
| Cube | 209870511087483 |
| Square root | 243.776537 (= 3√6603) |
| Digit sum / digital root | 27 / 9 |
| Collatz steps to 1 | 73 |
| Scientific notation | 5.9427 × |
59427 in other forms
| Form | Value |
|---|---|
| In words | fifty-nine thousand four hundred and twenty-seven |
| Binary (base 2) | 1110100000100011 |
| Octal (base 8) | 164043 |
| Hexadecimal (base 16) | E823 |
| Base 3 | 10000112000 |
| As time | 59427 seconds = 16 h 30 min 27 s |
Is 59427 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | Yes (59427 ÷ 3 = 19809) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 3) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 2) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 3) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 4) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 3) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | Yes (59427 ÷ 9 = 6603) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 7) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 5) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 3) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 59427 a prime number?
No. 59427 = × 31 × 71, so it is divisible by 3.
What are the factors of 59427?
1, 3, 9, 27, 31, 71, 93, 213, 279, 639, 837, 1917, 2201, 6603, 19809, 59427.
What is 59427 in binary?
1110100000100011 (hexadecimal E823, octal 164043).
What is the square root of 59427?
About 243.7765, exactly 3√6603.
Is 59427 divisible by 3?
Yes. Its digits add up to 27, a multiple of 3.
What is special about the number 59427?
59427 is a Harshad number: divisible by its digit sum 27.