The number 59425
59425 is a composite number with 6 divisors. Its prime factorisation is Ć 2377. Divisors (6): 1, 5, 25, 2377, 11885, 59425.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 59425: a Harshad number: divisible by its digit sum 25.
- 2
59425 is composite. Its prime factorisation is
- 3
The divisors add up to 73718; without 59425 itself that is 14293, so 59425 is deficient (14293 is less than 59425). Euler's totient Ļ(59425) = 47520 numbers up to 59425 share no factor with it.
- 4
The digits of 59425 add up to 25, and repeating that until one digit is left gives the digital root 7. The Collatz sequence (halve if even, else 3n+1) takes 73 steps to reach 1.
LaTeX source of the formulas on this page
\[ 59425 = 5^{2} \times 2377 \]59425 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 6 |
| Sum of divisors | 73718 |
| Euler totient Ļ(n) | 47520 |
| Square | 3531330625 |
| Cube | 209849322390625 |
| Square root | 243.772435 (= 5ā2377) |
| Digit sum / digital root | 25 / 7 |
| Collatz steps to 1 | 73 |
| Scientific notation | 5.9425 Ć |
59425 in other forms
| Form | Value |
|---|---|
| In words | fifty-nine thousand four hundred and twenty-five |
| Binary (base 2) | 1110100000100001 |
| Octal (base 8) | 164041 |
| Hexadecimal (base 16) | E821 |
| Base 3 | 10000111221 |
| As time | 59425 seconds = 16 h 30 min 25 s |
Is 59425 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 1) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 1) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | Yes (59425 Ć· 5 = 11885) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 1) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 2) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 1) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 7) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 5) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 3) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 1) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 59425 a prime number?
No. 59425 = Ć 2377, so it is divisible by 5.
What are the factors of 59425?
1, 5, 25, 2377, 11885, 59425.
What is 59425 in binary?
1110100000100001 (hexadecimal E821, octal 164041).
What is the square root of 59425?
About 243.7724, exactly 5ā2377.
Is 59425 divisible by 3?
No. Its digits add up to 25, which is not a multiple of 3.
What is special about the number 59425?
59425 is a Harshad number: divisible by its digit sum 25.