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The number 59117

59117 is a composite number with 4 divisors. Its prime factorisation is 31 × 1907. Divisors (4): 1, 31, 1907, 59117.

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How to work it out

  1. 1

    What is special about 59117: a semiprime: 31 × 1907, the product of two primes.

  2. 2

    59117 is composite. Its prime factorisation is

    59117=31×190759117 = 31 \times 1907
  3. 3

    The divisors add up to 61056; without 59117 itself that is 1939, so 59117 is deficient (1939 is less than 59117). Euler's totient φ(59117) = 57180 numbers up to 59117 share no factor with it.

  4. 4

    The digits of 59117 add up to 23, and repeating that until one digit is left gives the digital root 5. The Collatz sequence (halve if even, else 3n+1) takes 197 steps to reach 1.

LaTeX source of the formulas on this page
\[ 59117 = 31 \times 1907 \]

59117 at a glance

PropertyValue
Typecomposite
Number of divisors4
Sum of divisors61056
Euler totient φ(n)57180
Square3494819689
Cube206603255554613
Square root243.139877
Digit sum / digital root23 / 5
Collatz steps to 1197
Scientific notation5.9117 × 10410^{4}

59117 in other forms

FormValue
In wordsfifty-nine thousand one hundred and seventeen
Binary (base 2)1110011011101101
Octal (base 8)163355
Hexadecimal (base 16)E6ED
Base 310000002112
As time59117 seconds = 16 h 25 min 17 s

Is 59117 divisible by 2 to 12?

DivisorAnswerRule
2No (remainder 1)A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8).
3No (remainder 2)A number is divisible by 3 if the digits add up to a multiple of 3.
4No (remainder 1)A number is divisible by 4 if the last two digits make a multiple of 4.
5No (remainder 2)A number is divisible by 5 if the last digit is 0 or 5.
6No (remainder 5)A number is divisible by 6 if it is divisible by both 2 and 3.
7No (remainder 2)A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7.
8No (remainder 5)A number is divisible by 8 if the last three digits make a multiple of 8.
9No (remainder 5)A number is divisible by 9 if the digits add up to a multiple of 9.
10No (remainder 7)A number is divisible by 10 if the last digit is 0.
11No (remainder 3)A number is divisible by 11 if the alternating sum of the digits is a multiple of 11.
12No (remainder 5)A number is divisible by 12 if it is divisible by both 3 and 4.

Questions

Is 59117 a prime number?

No. 59117 = 31 × 1907, so it is divisible by 31.

What are the factors of 59117?

1, 31, 1907, 59117.

What is 59117 in binary?

1110011011101101 (hexadecimal E6ED, octal 163355).

What is the square root of 59117?

About 243.1399.

Is 59117 divisible by 3?

No. Its digits add up to 23, which is not a multiple of 3.

What is special about the number 59117?

59117 is a semiprime: 31 × 1907, the product of two primes.

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