The number 58423
58423 is a composite number with 4 divisors. Its prime factorisation is 37 × 1579. Divisors (4): 1, 37, 1579, 58423.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 58423: a semiprime: 37 × 1579, the product of two primes.
- 2
58423 is composite. Its prime factorisation is
- 3
The divisors add up to 60040; without 58423 itself that is 1617, so 58423 is deficient (1617 is less than 58423). Euler's totient φ(58423) = 56808 numbers up to 58423 share no factor with it.
- 4
The digits of 58423 add up to 22, and repeating that until one digit is left gives the digital root 4. The Collatz sequence (halve if even, else 3n+1) takes 228 steps to reach 1.
LaTeX source of the formulas on this page
\[ 58423 = 37 \times 1579 \]
58423 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 4 |
| Sum of divisors | 60040 |
| Euler totient φ(n) | 56808 |
| Square | 3413246929 |
| Cube | 199412125332967 |
| Square root | 241.708502 |
| Digit sum / digital root | 22 / 4 |
| Collatz steps to 1 | 228 |
| Scientific notation | 5.8423 × |
58423 in other forms
| Form | Value |
|---|---|
| In words | fifty-eight thousand four hundred and twenty-three |
| Binary (base 2) | 1110010000110111 |
| Octal (base 8) | 162067 |
| Hexadecimal (base 16) | E437 |
| Base 3 | 2222010211 |
| As time | 58423 seconds = 16 h 13 min 43 s |
Is 58423 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 1) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 3) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 3) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 1) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 1) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 7) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 4) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 3) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 2) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 7) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 58423 a prime number?
No. 58423 = 37 × 1579, so it is divisible by 37.
What are the factors of 58423?
1, 37, 1579, 58423.
What is 58423 in binary?
1110010000110111 (hexadecimal E437, octal 162067).
What is the square root of 58423?
About 241.7085.
Is 58423 divisible by 3?
No. Its digits add up to 22, which is not a multiple of 3.
What is special about the number 58423?
58423 is a semiprime: 37 × 1579, the product of two primes.