The number 58087
58087 is a composite number with 4 divisors. Its prime factorisation is 29 × 2003. Divisors (4): 1, 29, 2003, 58087.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 58087: a semiprime: 29 × 2003, the product of two primes.
- 2
58087 is composite. Its prime factorisation is
- 3
The divisors add up to 60120; without 58087 itself that is 2033, so 58087 is deficient (2033 is less than 58087). Euler's totient φ(58087) = 56056 numbers up to 58087 share no factor with it.
- 4
The digits of 58087 add up to 28, and repeating that until one digit is left gives the digital root 1. The Collatz sequence (halve if even, else 3n+1) takes 197 steps to reach 1.
LaTeX source of the formulas on this page
\[ 58087 = 29 \times 2003 \]
58087 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 4 |
| Sum of divisors | 60120 |
| Euler totient φ(n) | 56056 |
| Square | 3374099569 |
| Cube | 195991321664503 |
| Square root | 241.012448 |
| Digit sum / digital root | 28 / 1 |
| Collatz steps to 1 | 197 |
| Scientific notation | 5.8087 × |
58087 in other forms
| Form | Value |
|---|---|
| In words | fifty-eight thousand and eighty-seven |
| Binary (base 2) | 1110001011100111 |
| Octal (base 8) | 161347 |
| Hexadecimal (base 16) | E2E7 |
| Base 3 | 2221200101 |
| As time | 58087 seconds = 16 h 8 min 7 s |
Is 58087 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 1) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 3) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 2) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 1) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 1) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 7) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 1) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 7) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 7) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 7) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 58087 a prime number?
No. 58087 = 29 × 2003, so it is divisible by 29.
What are the factors of 58087?
1, 29, 2003, 58087.
What is 58087 in binary?
1110001011100111 (hexadecimal E2E7, octal 161347).
What is the square root of 58087?
About 241.0124.
Is 58087 divisible by 3?
No. Its digits add up to 28, which is not a multiple of 3.
What is special about the number 58087?
58087 is a semiprime: 29 × 2003, the product of two primes.