The number 57753
57753 is a composite number with 20 divisors. Its prime factorisation is × 23 × 31. Divisors (20): 1, 3, 9, 23, 27, 31, 69, 81, 93, 207, 279, 621, 713, 837, 1863, 2139 … 57753.
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How to work it out
- 1
What is special about 57753: a Harshad number: divisible by its digit sum 27.
- 2
57753 is composite. Its prime factorisation is
- 3
The divisors add up to 92928; without 57753 itself that is 35175, so 57753 is deficient (35175 is less than 57753). Euler's totient φ(57753) = 35640 numbers up to 57753 share no factor with it.
- 4
The digits of 57753 add up to 27, and repeating that until one digit is left gives the digital root 9. The Collatz sequence (halve if even, else 3n+1) takes 47 steps to reach 1.
LaTeX source of the formulas on this page
\[ 57753 = 3^{4} \times 23 \times 31 \]57753 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 20 |
| Sum of divisors | 92928 |
| Euler totient φ(n) | 35640 |
| Square | 3335409009 |
| Cube | 192629876496777 |
| Square root | 240.318539 (= 9√713) |
| Digit sum / digital root | 27 / 9 |
| Collatz steps to 1 | 47 |
| Scientific notation | 5.7753 × |
57753 in other forms
| Form | Value |
|---|---|
| In words | fifty-seven thousand seven hundred and fifty-three |
| Binary (base 2) | 1110000110011001 |
| Octal (base 8) | 160631 |
| Hexadecimal (base 16) | E199 |
| Base 3 | 2221020000 |
| As time | 57753 seconds = 16 h 2 min 33 s |
Is 57753 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | Yes (57753 ÷ 3 = 19251) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 1) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 3) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 3) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 3) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 1) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | Yes (57753 ÷ 9 = 6417) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 3) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 3) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 9) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 57753 a prime number?
No. 57753 = × 23 × 31, so it is divisible by 3.
What are the factors of 57753?
1, 3, 9, 23, 27, 31, 69, 81, 93, 207, 279, 621, 713, 837, 1863, 2139, 2511, 6417, 19251, 57753.
What is 57753 in binary?
1110000110011001 (hexadecimal E199, octal 160631).
What is the square root of 57753?
About 240.3185, exactly 9√713.
Is 57753 divisible by 3?
Yes. Its digits add up to 27, a multiple of 3.
What is special about the number 57753?
57753 is a Harshad number: divisible by its digit sum 27.