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The number 5603

5603 is a composite number with 4 divisors. Its prime factorisation is 13 × 431. Divisors (4): 1, 13, 431, 5603.

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How to work it out

  1. 1

    What is special about 5603: a happy number: repeatedly adding the squares of its digits reaches 1; a semiprime: 13 × 431, the product of two primes.

  2. 2

    5603 is composite. Its prime factorisation is

    5603=13×4315603 = 13 \times 431
  3. 3

    The divisors add up to 6048; without 5603 itself that is 445, so 5603 is deficient (445 is less than 5603). Euler's totient φ(5603) = 5160 numbers up to 5603 share no factor with it.

  4. 4

    The digits of 5603 add up to 14, and repeating that until one digit is left gives the digital root 5. The Collatz sequence (halve if even, else 3n+1) takes 36 steps to reach 1.

LaTeX source of the formulas on this page
\[ 5603 = 13 \times 431 \]

5603 at a glance

PropertyValue
Typecomposite
Number of divisors4
Sum of divisors6048
Euler totient φ(n)5160
Square31393609
Cube175898391227
Square root74.853190
Digit sum / digital root14 / 5
Collatz steps to 136
Scientific notation5.603 × 10310^{3}

5603 in other forms

FormValue
In wordsfive thousand six hundred and three
Binary (base 2)1010111100011
Octal (base 8)12743
Hexadecimal (base 16)15E3
Base 321200112
As time5603 seconds = 1 h 33 min 23 s

Is 5603 divisible by 2 to 12?

DivisorAnswerRule
2No (remainder 1)A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8).
3No (remainder 2)A number is divisible by 3 if the digits add up to a multiple of 3.
4No (remainder 3)A number is divisible by 4 if the last two digits make a multiple of 4.
5No (remainder 3)A number is divisible by 5 if the last digit is 0 or 5.
6No (remainder 5)A number is divisible by 6 if it is divisible by both 2 and 3.
7No (remainder 3)A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7.
8No (remainder 3)A number is divisible by 8 if the last three digits make a multiple of 8.
9No (remainder 5)A number is divisible by 9 if the digits add up to a multiple of 9.
10No (remainder 3)A number is divisible by 10 if the last digit is 0.
11No (remainder 4)A number is divisible by 11 if the alternating sum of the digits is a multiple of 11.
12No (remainder 11)A number is divisible by 12 if it is divisible by both 3 and 4.

Questions

Is 5603 a prime number?

No. 5603 = 13 × 431, so it is divisible by 13.

What are the factors of 5603?

1, 13, 431, 5603.

What is 5603 in binary?

1010111100011 (hexadecimal 15E3, octal 12743).

What is the square root of 5603?

About 74.8532.

Is 5603 divisible by 3?

No. Its digits add up to 14, which is not a multiple of 3.

What is special about the number 5603?

5603 is a happy number: repeatedly adding the squares of its digits reaches 1; a semiprime: 13 × 431, the product of two primes.

All about 5603

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