The number 55397
55397 is a composite number with 4 divisors. Its prime factorisation is 31 × 1787. Divisors (4): 1, 31, 1787, 55397.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 55397: a semiprime: 31 × 1787, the product of two primes.
- 2
55397 is composite. Its prime factorisation is
- 3
The divisors add up to 57216; without 55397 itself that is 1819, so 55397 is deficient (1819 is less than 55397). Euler's totient φ(55397) = 53580 numbers up to 55397 share no factor with it.
- 4
The digits of 55397 add up to 29, and repeating that until one digit is left gives the digital root 2. The Collatz sequence (halve if even, else 3n+1) takes 91 steps to reach 1.
LaTeX source of the formulas on this page
\[ 55397 = 31 \times 1787 \]
55397 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 4 |
| Sum of divisors | 57216 |
| Euler totient φ(n) | 53580 |
| Square | 3068827609 |
| Cube | 170003843055773 |
| Square root | 235.365673 |
| Digit sum / digital root | 29 / 2 |
| Collatz steps to 1 | 91 |
| Scientific notation | 5.5397 × |
55397 in other forms
| Form | Value |
|---|---|
| In words | fifty-five thousand three hundred and ninety-seven |
| Binary (base 2) | 1101100001100101 |
| Octal (base 8) | 154145 |
| Hexadecimal (base 16) | D865 |
| Base 3 | 2210222202 |
| As time | 55397 seconds = 15 h 23 min 17 s |
Is 55397 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 2) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 1) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 2) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 5) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 6) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 5) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 2) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 7) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 1) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 5) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 55397 a prime number?
No. 55397 = 31 × 1787, so it is divisible by 31.
What are the factors of 55397?
1, 31, 1787, 55397.
What is 55397 in binary?
1101100001100101 (hexadecimal D865, octal 154145).
What is the square root of 55397?
About 235.3657.
Is 55397 divisible by 3?
No. Its digits add up to 29, which is not a multiple of 3.
What is special about the number 55397?
55397 is a semiprime: 31 × 1787, the product of two primes.