The number 55301
55301 is a composite number with 4 divisors. Its prime factorisation is 17 × 3253. Divisors (4): 1, 17, 3253, 55301.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 55301: a semiprime: 17 × 3253, the product of two primes.
- 2
55301 is composite. Its prime factorisation is
- 3
The divisors add up to 58572; without 55301 itself that is 3271, so 55301 is deficient (3271 is less than 55301). Euler's totient φ(55301) = 52032 numbers up to 55301 share no factor with it.
- 4
The digits of 55301 add up to 14, and repeating that until one digit is left gives the digital root 5. The Collatz sequence (halve if even, else 3n+1) takes 91 steps to reach 1.
LaTeX source of the formulas on this page
\[ 55301 = 17 \times 3253 \]
55301 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 4 |
| Sum of divisors | 58572 |
| Euler totient φ(n) | 52032 |
| Square | 3058200601 |
| Cube | 169121551435901 |
| Square root | 235.161647 |
| Digit sum / digital root | 14 / 5 |
| Collatz steps to 1 | 91 |
| Scientific notation | 5.5301 × |
55301 in other forms
| Form | Value |
|---|---|
| In words | fifty-five thousand three hundred and one |
| Binary (base 2) | 1101100000000101 |
| Octal (base 8) | 154005 |
| Hexadecimal (base 16) | D805 |
| Base 3 | 2210212012 |
| As time | 55301 seconds = 15 h 21 min 41 s |
Is 55301 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 2) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 1) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 1) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 5) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 1) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 5) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 5) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 1) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 4) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 5) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 55301 a prime number?
No. 55301 = 17 × 3253, so it is divisible by 17.
What are the factors of 55301?
1, 17, 3253, 55301.
What is 55301 in binary?
1101100000000101 (hexadecimal D805, octal 154005).
What is the square root of 55301?
About 235.1616.
Is 55301 divisible by 3?
No. Its digits add up to 14, which is not a multiple of 3.
What is special about the number 55301?
55301 is a semiprime: 17 × 3253, the product of two primes.