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The number 53975

53975 is a composite number with 12 divisors. Its prime factorisation is 525^{2} × 17 × 127. Divisors (12): 1, 5, 17, 25, 85, 127, 425, 635, 2159, 3175, 10795, 53975.

Number

Pick any whole number from 1 to 100,000.

How to work it out

  1. 1

    53975 has no famous special property in the usual lists (prime, square, cube, triangular, Fibonacci, palindrome, perfect), but it is still a composite number.

  2. 2

    53975 is composite. Its prime factorisation is

    53975=52×17×12753975 = 5^{2} \times 17 \times 127
  3. 3

    The divisors add up to 71424; without 53975 itself that is 17449, so 53975 is deficient (17449 is less than 53975). Euler's totient φ(53975) = 40320 numbers up to 53975 share no factor with it.

  4. 4

    The digits of 53975 add up to 29, and repeating that until one digit is left gives the digital root 2. The Collatz sequence (halve if even, else 3n+1) takes 140 steps to reach 1.

LaTeX source of the formulas on this page
\[ 53975 = 5^{2} \times 17 \times 127 \]

53975 at a glance

PropertyValue
Typecomposite
Number of divisors12
Sum of divisors71424
Euler totient φ(n)40320
Square2913300625
Cube157245401234375
Square root232.325203 (= 5√2159)
Digit sum / digital root29 / 2
Collatz steps to 1140
Scientific notation5.3975 × 10410^{4}

53975 in other forms

FormValue
In wordsfifty-three thousand nine hundred and seventy-five
Binary (base 2)1101001011010111
Octal (base 8)151327
Hexadecimal (base 16)D2D7
Base 32202001002
As time53975 seconds = 14 h 59 min 35 s

Is 53975 divisible by 2 to 12?

DivisorAnswerRule
2No (remainder 1)A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8).
3No (remainder 2)A number is divisible by 3 if the digits add up to a multiple of 3.
4No (remainder 3)A number is divisible by 4 if the last two digits make a multiple of 4.
5Yes (53975 ÷ 5 = 10795)A number is divisible by 5 if the last digit is 0 or 5.
6No (remainder 5)A number is divisible by 6 if it is divisible by both 2 and 3.
7No (remainder 5)A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7.
8No (remainder 7)A number is divisible by 8 if the last three digits make a multiple of 8.
9No (remainder 2)A number is divisible by 9 if the digits add up to a multiple of 9.
10No (remainder 5)A number is divisible by 10 if the last digit is 0.
11No (remainder 9)A number is divisible by 11 if the alternating sum of the digits is a multiple of 11.
12No (remainder 11)A number is divisible by 12 if it is divisible by both 3 and 4.

Questions

Is 53975 a prime number?

No. 53975 = 525^{2} × 17 × 127, so it is divisible by 5.

What are the factors of 53975?

1, 5, 17, 25, 85, 127, 425, 635, 2159, 3175, 10795, 53975.

What is 53975 in binary?

1101001011010111 (hexadecimal D2D7, octal 151327).

What is the square root of 53975?

About 232.3252, exactly 5√2159.

Is 53975 divisible by 3?

No. Its digits add up to 29, which is not a multiple of 3.

What is special about the number 53975?

It is a composite number with 12 divisors.

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    53975: is it prime? Factors, square root, binary, Roman numeral | WordGPT