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The number 53793

53793 is a composite number with 12 divisors. Its prime factorisation is 323^{2} × 43 × 139. Divisors (12): 1, 3, 9, 43, 129, 139, 387, 417, 1251, 5977, 17931, 53793.

Number

Pick any whole number from 1 to 100,000.

How to work it out

  1. 1

    53793 has no famous special property in the usual lists (prime, square, cube, triangular, Fibonacci, palindrome, perfect), but it is still a composite number.

  2. 2

    53793 is composite. Its prime factorisation is

    53793=32×43×13953793 = 3^{2} \times 43 \times 139
  3. 3

    The divisors add up to 80080; without 53793 itself that is 26287, so 53793 is deficient (26287 is less than 53793). Euler's totient φ(53793) = 34776 numbers up to 53793 share no factor with it.

  4. 4

    The digits of 53793 add up to 27, and repeating that until one digit is left gives the digital root 9. The Collatz sequence (halve if even, else 3n+1) takes 215 steps to reach 1.

LaTeX source of the formulas on this page
\[ 53793 = 3^{2} \times 43 \times 139 \]

53793 at a glance

PropertyValue
Typecomposite
Number of divisors12
Sum of divisors80080
Euler totient φ(n)34776
Square2893686849
Cube155660096668257
Square root231.933180 (= 3√5977)
Digit sum / digital root27 / 9
Collatz steps to 1215
Scientific notation5.3793 × 10410^{4}

53793 in other forms

FormValue
In wordsfifty-three thousand seven hundred and ninety-three
Binary (base 2)1101001000100001
Octal (base 8)151041
Hexadecimal (base 16)D221
Base 32201210100
As time53793 seconds = 14 h 56 min 33 s

Is 53793 divisible by 2 to 12?

DivisorAnswerRule
2No (remainder 1)A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8).
3Yes (53793 ÷ 3 = 17931)A number is divisible by 3 if the digits add up to a multiple of 3.
4No (remainder 1)A number is divisible by 4 if the last two digits make a multiple of 4.
5No (remainder 3)A number is divisible by 5 if the last digit is 0 or 5.
6No (remainder 3)A number is divisible by 6 if it is divisible by both 2 and 3.
7No (remainder 5)A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7.
8No (remainder 1)A number is divisible by 8 if the last three digits make a multiple of 8.
9Yes (53793 ÷ 9 = 5977)A number is divisible by 9 if the digits add up to a multiple of 9.
10No (remainder 3)A number is divisible by 10 if the last digit is 0.
11No (remainder 3)A number is divisible by 11 if the alternating sum of the digits is a multiple of 11.
12No (remainder 9)A number is divisible by 12 if it is divisible by both 3 and 4.

Questions

Is 53793 a prime number?

No. 53793 = 323^{2} × 43 × 139, so it is divisible by 3.

What are the factors of 53793?

1, 3, 9, 43, 129, 139, 387, 417, 1251, 5977, 17931, 53793.

What is 53793 in binary?

1101001000100001 (hexadecimal D221, octal 151041).

What is the square root of 53793?

About 231.9332, exactly 3√5977.

Is 53793 divisible by 3?

Yes. Its digits add up to 27, a multiple of 3.

What is special about the number 53793?

It is a composite number with 12 divisors.

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    53793: is it prime? Factors, square root, binary, Roman numeral | WordGPT