The number 53729
53729 is a composite number with 4 divisors. Its prime factorisation is 13 × 4133. Divisors (4): 1, 13, 4133, 53729.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 53729: a semiprime: 13 × 4133, the product of two primes.
- 2
53729 is composite. Its prime factorisation is
- 3
The divisors add up to 57876; without 53729 itself that is 4147, so 53729 is deficient (4147 is less than 53729). Euler's totient φ(53729) = 49584 numbers up to 53729 share no factor with it.
- 4
The digits of 53729 add up to 26, and repeating that until one digit is left gives the digital root 8. The Collatz sequence (halve if even, else 3n+1) takes 215 steps to reach 1.
LaTeX source of the formulas on this page
\[ 53729 = 13 \times 4133 \]
53729 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 4 |
| Sum of divisors | 57876 |
| Euler totient φ(n) | 49584 |
| Square | 2886805441 |
| Cube | 155105169539489 |
| Square root | 231.795168 |
| Digit sum / digital root | 26 / 8 |
| Collatz steps to 1 | 215 |
| Scientific notation | 5.3729 × |
53729 in other forms
| Form | Value |
|---|---|
| In words | fifty-three thousand seven hundred and twenty-nine |
| Binary (base 2) | 1101000111100001 |
| Octal (base 8) | 150741 |
| Hexadecimal (base 16) | D1E1 |
| Base 3 | 2201200222 |
| As time | 53729 seconds = 14 h 55 min 29 s |
Is 53729 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 2) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 1) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 4) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 5) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 4) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 1) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 8) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 9) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 5) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 5) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 53729 a prime number?
No. 53729 = 13 × 4133, so it is divisible by 13.
What are the factors of 53729?
1, 13, 4133, 53729.
What is 53729 in binary?
1101000111100001 (hexadecimal D1E1, octal 150741).
What is the square root of 53729?
About 231.7952.
Is 53729 divisible by 3?
No. Its digits add up to 26, which is not a multiple of 3.
What is special about the number 53729?
53729 is a semiprime: 13 × 4133, the product of two primes.