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The number 537

537 is a composite number with 4 divisors. Its prime factorisation is 3 × 179. Divisors (4): 1, 3, 179, 537.

Number

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How to work it out

  1. 1

    What is special about 537: a semiprime: 3 × 179, the product of two primes.

  2. 2

    537 is composite. Its prime factorisation is

    537=3×179537 = 3 \times 179
  3. 3

    The divisors add up to 720; without 537 itself that is 183, so 537 is deficient (183 is less than 537). Euler's totient φ(537) = 356 numbers up to 537 share no factor with it.

  4. 4

    The digits of 537 add up to 15, and repeating that until one digit is left gives the digital root 6. The Collatz sequence (halve if even, else 3n+1) takes 22 steps to reach 1.

LaTeX source of the formulas on this page
\[ 537 = 3 \times 179 \]

537 at a glance

PropertyValue
Typecomposite
Number of divisors4
Sum of divisors720
Euler totient φ(n)356
Square288369
Cube154854153
Square root23.173260
Digit sum / digital root15 / 6
Collatz steps to 122
Scientific notation5.37 × 10210^{2}

537 in other forms

FormValue
In wordsfive hundred and thirty-seven
Roman numeralsDXXXVII
Binary (base 2)1000011001
Octal (base 8)1031
Hexadecimal (base 16)219
Base 3201220
As time537 seconds = 8 min 57 s

Is 537 divisible by 2 to 12?

DivisorAnswerRule
2No (remainder 1)A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8).
3Yes (537 ÷ 3 = 179)A number is divisible by 3 if the digits add up to a multiple of 3.
4No (remainder 1)A number is divisible by 4 if the last two digits make a multiple of 4.
5No (remainder 2)A number is divisible by 5 if the last digit is 0 or 5.
6No (remainder 3)A number is divisible by 6 if it is divisible by both 2 and 3.
7No (remainder 5)A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7.
8No (remainder 1)A number is divisible by 8 if the last three digits make a multiple of 8.
9No (remainder 6)A number is divisible by 9 if the digits add up to a multiple of 9.
10No (remainder 7)A number is divisible by 10 if the last digit is 0.
11No (remainder 9)A number is divisible by 11 if the alternating sum of the digits is a multiple of 11.
12No (remainder 9)A number is divisible by 12 if it is divisible by both 3 and 4.

Questions

Is 537 a prime number?

No. 537 = 3 × 179, so it is divisible by 3.

What are the factors of 537?

1, 3, 179, 537.

What is 537 in binary?

1000011001 (hexadecimal 219, octal 1031).

What is the square root of 537?

About 23.1733.

What is 537 in Roman numerals?

DXXXVII.

Is 537 divisible by 3?

Yes. Its digits add up to 15, a multiple of 3.

What is special about the number 537?

537 is a semiprime: 3 × 179, the product of two primes.

All about 537

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    537: is it prime? Factors, square root, binary, Roman numeral | WordGPT