The number 53509
53509 is a composite number with 4 divisors. Its prime factorisation is 73 × 733. Divisors (4): 1, 73, 733, 53509.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 53509: a semiprime: 73 × 733, the product of two primes.
- 2
53509 is composite. Its prime factorisation is
- 3
The divisors add up to 54316; without 53509 itself that is 807, so 53509 is deficient (807 is less than 53509). Euler's totient φ(53509) = 52704 numbers up to 53509 share no factor with it.
- 4
The digits of 53509 add up to 22, and repeating that until one digit is left gives the digital root 4. The Collatz sequence (halve if even, else 3n+1) takes 47 steps to reach 1.
LaTeX source of the formulas on this page
\[ 53509 = 73 \times 733 \]
53509 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 4 |
| Sum of divisors | 54316 |
| Euler totient φ(n) | 52704 |
| Square | 2863213081 |
| Cube | 153207668751229 |
| Square root | 231.320125 |
| Digit sum / digital root | 22 / 4 |
| Collatz steps to 1 | 47 |
| Scientific notation | 5.3509 × |
53509 in other forms
| Form | Value |
|---|---|
| In words | fifty-three thousand five hundred and nine |
| Binary (base 2) | 1101000100000101 |
| Octal (base 8) | 150405 |
| Hexadecimal (base 16) | D105 |
| Base 3 | 2201101211 |
| As time | 53509 seconds = 14 h 51 min 49 s |
Is 53509 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 1) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 1) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 4) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 1) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 1) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 5) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 4) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 9) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 5) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 1) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 53509 a prime number?
No. 53509 = 73 × 733, so it is divisible by 73.
What are the factors of 53509?
1, 73, 733, 53509.
What is 53509 in binary?
1101000100000101 (hexadecimal D105, octal 150405).
What is the square root of 53509?
About 231.3201.
Is 53509 divisible by 3?
No. Its digits add up to 22, which is not a multiple of 3.
What is special about the number 53509?
53509 is a semiprime: 73 × 733, the product of two primes.