The number 53473
53473 is a composite number with 4 divisors. Its prime factorisation is 7 × 7639. Divisors (4): 1, 7, 7639, 53473.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 53473: a semiprime: 7 × 7639, the product of two primes.
- 2
53473 is composite. Its prime factorisation is
- 3
The divisors add up to 61120; without 53473 itself that is 7647, so 53473 is deficient (7647 is less than 53473). Euler's totient φ(53473) = 45828 numbers up to 53473 share no factor with it.
- 4
The digits of 53473 add up to 22, and repeating that until one digit is left gives the digital root 4. The Collatz sequence (halve if even, else 3n+1) takes 277 steps to reach 1.
LaTeX source of the formulas on this page
\[ 53473 = 7 \times 7639 \]
53473 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 4 |
| Sum of divisors | 61120 |
| Euler totient φ(n) | 45828 |
| Square | 2859361729 |
| Cube | 152898649734817 |
| Square root | 231.242297 |
| Digit sum / digital root | 22 / 4 |
| Collatz steps to 1 | 277 |
| Scientific notation | 5.3473 × |
53473 in other forms
| Form | Value |
|---|---|
| In words | fifty-three thousand four hundred and seventy-three |
| Binary (base 2) | 1101000011100001 |
| Octal (base 8) | 150341 |
| Hexadecimal (base 16) | D0E1 |
| Base 3 | 2201100111 |
| As time | 53473 seconds = 14 h 51 min 13 s |
Is 53473 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 1) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 1) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 3) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 1) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | Yes (53473 ÷ 7 = 7639) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 1) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 4) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 3) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 2) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 1) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 53473 a prime number?
No. 53473 = 7 × 7639, so it is divisible by 7.
What are the factors of 53473?
1, 7, 7639, 53473.
What is 53473 in binary?
1101000011100001 (hexadecimal D0E1, octal 150341).
What is the square root of 53473?
About 231.2423.
Is 53473 divisible by 3?
No. Its digits add up to 22, which is not a multiple of 3.
What is special about the number 53473?
53473 is a semiprime: 7 × 7639, the product of two primes.