The number 53429
53429 is a composite number with 6 divisors. Its prime factorisation is Ć 101. Divisors (6): 1, 23, 101, 529, 2323, 53429.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 53429: a Harshad number: divisible by its digit sum 23.
- 2
53429 is composite. Its prime factorisation is
- 3
The divisors add up to 56406; without 53429 itself that is 2977, so 53429 is deficient (2977 is less than 53429). Euler's totient Ļ(53429) = 50600 numbers up to 53429 share no factor with it.
- 4
The digits of 53429 add up to 23, and repeating that until one digit is left gives the digital root 5. The Collatz sequence (halve if even, else 3n+1) takes 96 steps to reach 1.
LaTeX source of the formulas on this page
\[ 53429 = 23^{2} \times 101 \]53429 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 6 |
| Sum of divisors | 56406 |
| Euler totient Ļ(n) | 50600 |
| Square | 2854658041 |
| Cube | 152521524472589 |
| Square root | 231.147139 (= 23ā101) |
| Digit sum / digital root | 23 / 5 |
| Collatz steps to 1 | 96 |
| Scientific notation | 5.3429 Ć |
53429 in other forms
| Form | Value |
|---|---|
| In words | fifty-three thousand four hundred and twenty-nine |
| Binary (base 2) | 1101000010110101 |
| Octal (base 8) | 150265 |
| Hexadecimal (base 16) | D0B5 |
| Base 3 | 2201021212 |
| As time | 53429 seconds = 14 h 50 min 29 s |
Is 53429 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 2) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 1) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 4) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 5) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 5) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 5) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 5) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 9) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 2) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 5) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 53429 a prime number?
No. 53429 = Ć 101, so it is divisible by 23.
What are the factors of 53429?
1, 23, 101, 529, 2323, 53429.
What is 53429 in binary?
1101000010110101 (hexadecimal D0B5, octal 150265).
What is the square root of 53429?
About 231.1471, exactly 23ā101.
Is 53429 divisible by 3?
No. Its digits add up to 23, which is not a multiple of 3.
What is special about the number 53429?
53429 is a Harshad number: divisible by its digit sum 23.