The number 53421
53421 is a composite number with 4 divisors. Its prime factorisation is 3 × 17807. Divisors (4): 1, 3, 17807, 53421.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 53421: a semiprime: 3 × 17807, the product of two primes.
- 2
53421 is composite. Its prime factorisation is
- 3
The divisors add up to 71232; without 53421 itself that is 17811, so 53421 is deficient (17811 is less than 53421). Euler's totient φ(53421) = 35612 numbers up to 53421 share no factor with it.
- 4
The digits of 53421 add up to 15, and repeating that until one digit is left gives the digital root 6. The Collatz sequence (halve if even, else 3n+1) takes 96 steps to reach 1.
LaTeX source of the formulas on this page
\[ 53421 = 3 \times 17807 \]
53421 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 4 |
| Sum of divisors | 71232 |
| Euler totient φ(n) | 35612 |
| Square | 2853803241 |
| Cube | 152453022937461 |
| Square root | 231.129834 |
| Digit sum / digital root | 15 / 6 |
| Collatz steps to 1 | 96 |
| Scientific notation | 5.3421 × |
53421 in other forms
| Form | Value |
|---|---|
| In words | fifty-three thousand four hundred and twenty-one |
| Binary (base 2) | 1101000010101101 |
| Octal (base 8) | 150255 |
| Hexadecimal (base 16) | D0AD |
| Base 3 | 2201021120 |
| As time | 53421 seconds = 14 h 50 min 21 s |
Is 53421 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | Yes (53421 ÷ 3 = 17807) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 1) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 1) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 3) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 4) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 5) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 6) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 1) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 5) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 9) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 53421 a prime number?
No. 53421 = 3 × 17807, so it is divisible by 3.
What are the factors of 53421?
1, 3, 17807, 53421.
What is 53421 in binary?
1101000010101101 (hexadecimal D0AD, octal 150255).
What is the square root of 53421?
About 231.1298.
Is 53421 divisible by 3?
Yes. Its digits add up to 15, a multiple of 3.
What is special about the number 53421?
53421 is a semiprime: 3 × 17807, the product of two primes.