The number 53397
53397 is a composite number with 12 divisors. Its prime factorisation is × 17 × 349. Divisors (12): 1, 3, 9, 17, 51, 153, 349, 1047, 3141, 5933, 17799, 53397.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
53397 has no famous special property in the usual lists (prime, square, cube, triangular, Fibonacci, palindrome, perfect), but it is still a composite number.
- 2
53397 is composite. Its prime factorisation is
- 3
The divisors add up to 81900; without 53397 itself that is 28503, so 53397 is deficient (28503 is less than 53397). Euler's totient φ(53397) = 33408 numbers up to 53397 share no factor with it.
- 4
The digits of 53397 add up to 27, and repeating that until one digit is left gives the digital root 9. The Collatz sequence (halve if even, else 3n+1) takes 70 steps to reach 1.
LaTeX source of the formulas on this page
\[ 53397 = 3^{2} \times 17 \times 349 \]53397 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 12 |
| Sum of divisors | 81900 |
| Euler totient φ(n) | 33408 |
| Square | 2851239609 |
| Cube | 152247641401773 |
| Square root | 231.077909 (= 3√5933) |
| Digit sum / digital root | 27 / 9 |
| Collatz steps to 1 | 70 |
| Scientific notation | 5.3397 × |
53397 in other forms
| Form | Value |
|---|---|
| In words | fifty-three thousand three hundred and ninety-seven |
| Binary (base 2) | 1101000010010101 |
| Octal (base 8) | 150225 |
| Hexadecimal (base 16) | D095 |
| Base 3 | 2201020200 |
| As time | 53397 seconds = 14 h 49 min 57 s |
Is 53397 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | Yes (53397 ÷ 3 = 17799) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 1) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 2) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 3) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 1) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 5) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | Yes (53397 ÷ 9 = 5933) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 7) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 3) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 9) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 53397 a prime number?
No. 53397 = × 17 × 349, so it is divisible by 3.
What are the factors of 53397?
1, 3, 9, 17, 51, 153, 349, 1047, 3141, 5933, 17799, 53397.
What is 53397 in binary?
1101000010010101 (hexadecimal D095, octal 150225).
What is the square root of 53397?
About 231.0779, exactly 3√5933.
Is 53397 divisible by 3?
Yes. Its digits add up to 27, a multiple of 3.
What is special about the number 53397?
It is a composite number with 12 divisors.