The number 5329
5329 is a perfect square (73²). Its prime factorisation is . Divisors (3): 1, 73, 5329.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 5329: a perfect square (73²); the square of a prime (73²).
- 2
5329 is composite. Its prime factorisation is
- 3
The divisors add up to 5403; without 5329 itself that is 74, so 5329 is deficient (74 is less than 5329). Euler's totient φ(5329) = 5256 numbers up to 5329 share no factor with it.
- 4
The digits of 5329 add up to 19, and repeating that until one digit is left gives the digital root 1. The Collatz sequence (halve if even, else 3n+1) takes 54 steps to reach 1.
LaTeX source of the formulas on this page
\[ 5329 = 73^{2} \]5329 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 3 |
| Sum of divisors | 5403 |
| Euler totient φ(n) | 5256 |
| Square | 28398241 |
| Cube | 151334226289 |
| Square root | 73 |
| Digit sum / digital root | 19 / 1 |
| Collatz steps to 1 | 54 |
| Scientific notation | 5.329 × |
| Perfect power |
5329 in other forms
| Form | Value |
|---|---|
| In words | five thousand three hundred and twenty-nine |
| Binary (base 2) | 1010011010001 |
| Octal (base 8) | 12321 |
| Hexadecimal (base 16) | 14D1 |
| Base 3 | 21022101 |
| As time | 5329 seconds = 1 h 28 min 49 s |
Is 5329 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 1) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 1) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 4) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 1) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 2) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 1) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 1) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 9) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 5) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 1) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 5329 a prime number?
No. 5329 = , so it is divisible by 73.
What are the factors of 5329?
1, 73, 5329.
What is 5329 in binary?
1010011010001 (hexadecimal 14D1, octal 12321).
What is the square root of 5329?
73, because 73 × 73 = 5329.
Is 5329 divisible by 3?
No. Its digits add up to 19, which is not a multiple of 3.
What is special about the number 5329?
5329 is a perfect square (73²); the square of a prime (73²).