The number 53273
53273 is a composite number with 8 divisors. Its prime factorisation is 11 × 29 × 167. Divisors (8): 1, 11, 29, 167, 319, 1837, 4843, 53273.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
53273 has no famous special property in the usual lists (prime, square, cube, triangular, Fibonacci, palindrome, perfect), but it is still a composite number.
- 2
53273 is composite. Its prime factorisation is
- 3
The divisors add up to 60480; without 53273 itself that is 7207, so 53273 is deficient (7207 is less than 53273). Euler's totient φ(53273) = 46480 numbers up to 53273 share no factor with it.
- 4
The digits of 53273 add up to 20, and repeating that until one digit is left gives the digital root 2. The Collatz sequence (halve if even, else 3n+1) takes 171 steps to reach 1.
LaTeX source of the formulas on this page
\[ 53273 = 11 \times 29 \times 167 \]
53273 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 8 |
| Sum of divisors | 60480 |
| Euler totient φ(n) | 46480 |
| Square | 2838012529 |
| Cube | 151189441457417 |
| Square root | 230.809445 |
| Digit sum / digital root | 20 / 2 |
| Collatz steps to 1 | 171 |
| Scientific notation | 5.3273 × |
53273 in other forms
| Form | Value |
|---|---|
| In words | fifty-three thousand two hundred and seventy-three |
| Binary (base 2) | 1101000000011001 |
| Octal (base 8) | 150031 |
| Hexadecimal (base 16) | D019 |
| Base 3 | 2201002002 |
| As time | 53273 seconds = 14 h 47 min 53 s |
Is 53273 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 2) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 1) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 3) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 5) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 3) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 1) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 2) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 3) | A number is divisible by 10 if the last digit is 0. |
| 11 | Yes (53273 ÷ 11 = 4843) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 5) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 53273 a prime number?
No. 53273 = 11 × 29 × 167, so it is divisible by 11.
What are the factors of 53273?
1, 11, 29, 167, 319, 1837, 4843, 53273.
What is 53273 in binary?
1101000000011001 (hexadecimal D019, octal 150031).
What is the square root of 53273?
About 230.8094.
Is 53273 divisible by 3?
No. Its digits add up to 20, which is not a multiple of 3.
What is special about the number 53273?
It is a composite number with 8 divisors.