The number 53221
53221 is a composite number with 4 divisors. Its prime factorisation is 7 × 7603. Divisors (4): 1, 7, 7603, 53221.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 53221: a semiprime: 7 × 7603, the product of two primes.
- 2
53221 is composite. Its prime factorisation is
- 3
The divisors add up to 60832; without 53221 itself that is 7611, so 53221 is deficient (7611 is less than 53221). Euler's totient φ(53221) = 45612 numbers up to 53221 share no factor with it.
- 4
The digits of 53221 add up to 13, and repeating that until one digit is left gives the digital root 4. The Collatz sequence (halve if even, else 3n+1) takes 78 steps to reach 1.
LaTeX source of the formulas on this page
\[ 53221 = 7 \times 7603 \]
53221 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 4 |
| Sum of divisors | 60832 |
| Euler totient φ(n) | 45612 |
| Square | 2832474841 |
| Cube | 150747143512861 |
| Square root | 230.696771 |
| Digit sum / digital root | 13 / 4 |
| Collatz steps to 1 | 78 |
| Scientific notation | 5.3221 × |
53221 in other forms
| Form | Value |
|---|---|
| In words | fifty-three thousand two hundred and twenty-one |
| Binary (base 2) | 1100111111100101 |
| Octal (base 8) | 147745 |
| Hexadecimal (base 16) | CFE5 |
| Base 3 | 2201000011 |
| As time | 53221 seconds = 14 h 47 min 1 s |
Is 53221 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 1) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 1) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 1) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 1) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | Yes (53221 ÷ 7 = 7603) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 5) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 4) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 1) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 3) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 1) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 53221 a prime number?
No. 53221 = 7 × 7603, so it is divisible by 7.
What are the factors of 53221?
1, 7, 7603, 53221.
What is 53221 in binary?
1100111111100101 (hexadecimal CFE5, octal 147745).
What is the square root of 53221?
About 230.6968.
Is 53221 divisible by 3?
No. Its digits add up to 13, which is not a multiple of 3.
What is special about the number 53221?
53221 is a semiprime: 7 × 7603, the product of two primes.