The number 53108
53108 is a composite number with 24 divisors. Its prime factorisation is × 11 × 17 × 71. Divisors (24): 1, 2, 4, 11, 17, 22, 34, 44, 68, 71, 142, 187, 284, 374, 748, 781 … 53108.
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How to work it out
- 1
What is special about 53108: a Harshad number: divisible by its digit sum 17.
- 2
53108 is composite. Its prime factorisation is
- 3
The divisors add up to 108864; without 53108 itself that is 55756, so 53108 is abundant (55756 is more than 53108). Euler's totient φ(53108) = 22400 numbers up to 53108 share no factor with it.
- 4
The digits of 53108 add up to 17, and repeating that until one digit is left gives the digital root 8. The Collatz sequence (halve if even, else 3n+1) takes 47 steps to reach 1.
LaTeX source of the formulas on this page
\[ 53108 = 2^{2} \times 11 \times 17 \times 71 \]53108 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 24 |
| Sum of divisors | 108864 |
| Euler totient φ(n) | 22400 |
| Square | 2820459664 |
| Cube | 149788971835712 |
| Square root | 230.451730 (= 2√13277) |
| Digit sum / digital root | 17 / 8 |
| Collatz steps to 1 | 47 |
| Scientific notation | 5.3108 × |
53108 in other forms
| Form | Value |
|---|---|
| In words | fifty-three thousand one hundred and eight |
| Binary (base 2) | 1100111101110100 |
| Octal (base 8) | 147564 |
| Hexadecimal (base 16) | CF74 |
| Base 3 | 2200211222 |
| As time | 53108 seconds = 14 h 45 min 8 s |
Is 53108 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | Yes (53108 ÷ 2 = 26554) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 2) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | Yes (53108 ÷ 4 = 13277) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 3) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 2) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 6) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 4) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 8) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 8) | A number is divisible by 10 if the last digit is 0. |
| 11 | Yes (53108 ÷ 11 = 4828) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 8) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 53108 a prime number?
No. 53108 = × 11 × 17 × 71, so it is divisible by 2.
What are the factors of 53108?
1, 2, 4, 11, 17, 22, 34, 44, 68, 71, 142, 187, 284, 374, 748, 781, 1207, 1562, 2414, 3124, 4828, 13277, 26554, 53108.
What is 53108 in binary?
1100111101110100 (hexadecimal CF74, octal 147564).
What is the square root of 53108?
About 230.4517, exactly 2√13277.
Is 53108 divisible by 3?
No. Its digits add up to 17, which is not a multiple of 3.
What is special about the number 53108?
53108 is a Harshad number: divisible by its digit sum 17.