The number 53021
53021 is a composite number with 4 divisors. Its prime factorisation is 37 × 1433. Divisors (4): 1, 37, 1433, 53021.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 53021: a semiprime: 37 × 1433, the product of two primes.
- 2
53021 is composite. Its prime factorisation is
- 3
The divisors add up to 54492; without 53021 itself that is 1471, so 53021 is deficient (1471 is less than 53021). Euler's totient φ(53021) = 51552 numbers up to 53021 share no factor with it.
- 4
The digits of 53021 add up to 11, and repeating that until one digit is left gives the digital root 2. The Collatz sequence (halve if even, else 3n+1) takes 277 steps to reach 1.
LaTeX source of the formulas on this page
\[ 53021 = 37 \times 1433 \]
53021 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 4 |
| Sum of divisors | 54492 |
| Euler totient φ(n) | 51552 |
| Square | 2811226441 |
| Cube | 149054037128261 |
| Square root | 230.262893 |
| Digit sum / digital root | 11 / 2 |
| Collatz steps to 1 | 277 |
| Scientific notation | 5.3021 × |
53021 in other forms
| Form | Value |
|---|---|
| In words | fifty-three thousand and twenty-one |
| Binary (base 2) | 1100111100011101 |
| Octal (base 8) | 147435 |
| Hexadecimal (base 16) | CF1D |
| Base 3 | 2200201202 |
| As time | 53021 seconds = 14 h 43 min 41 s |
Is 53021 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 2) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 1) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 1) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 5) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 3) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 5) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 2) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 1) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 1) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 5) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 53021 a prime number?
No. 53021 = 37 × 1433, so it is divisible by 37.
What are the factors of 53021?
1, 37, 1433, 53021.
What is 53021 in binary?
1100111100011101 (hexadecimal CF1D, octal 147435).
What is the square root of 53021?
About 230.2629.
Is 53021 divisible by 3?
No. Its digits add up to 11, which is not a multiple of 3.
What is special about the number 53021?
53021 is a semiprime: 37 × 1433, the product of two primes.