The number 53009
53009 is a composite number with 8 divisors. Its prime factorisation is 11 × 61 × 79. Divisors (8): 1, 11, 61, 79, 671, 869, 4819, 53009.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
53009 has no famous special property in the usual lists (prime, square, cube, triangular, Fibonacci, palindrome, perfect), but it is still a composite number.
- 2
53009 is composite. Its prime factorisation is
- 3
The divisors add up to 59520; without 53009 itself that is 6511, so 53009 is deficient (6511 is less than 53009). Euler's totient φ(53009) = 46800 numbers up to 53009 share no factor with it.
- 4
The digits of 53009 add up to 17, and repeating that until one digit is left gives the digital root 8. The Collatz sequence (halve if even, else 3n+1) takes 78 steps to reach 1.
LaTeX source of the formulas on this page
\[ 53009 = 11 \times 61 \times 79 \]
53009 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 8 |
| Sum of divisors | 59520 |
| Euler totient φ(n) | 46800 |
| Square | 2809954081 |
| Cube | 148952855879729 |
| Square root | 230.236835 |
| Digit sum / digital root | 17 / 8 |
| Collatz steps to 1 | 78 |
| Scientific notation | 5.3009 × |
53009 in other forms
| Form | Value |
|---|---|
| In words | fifty-three thousand and nine |
| Binary (base 2) | 1100111100010001 |
| Octal (base 8) | 147421 |
| Hexadecimal (base 16) | CF11 |
| Base 3 | 2200201022 |
| As time | 53009 seconds = 14 h 43 min 29 s |
Is 53009 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 2) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 1) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 4) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 5) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 5) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 1) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 8) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 9) | A number is divisible by 10 if the last digit is 0. |
| 11 | Yes (53009 ÷ 11 = 4819) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 5) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 53009 a prime number?
No. 53009 = 11 × 61 × 79, so it is divisible by 11.
What are the factors of 53009?
1, 11, 61, 79, 671, 869, 4819, 53009.
What is 53009 in binary?
1100111100010001 (hexadecimal CF11, octal 147421).
What is the square root of 53009?
About 230.2368.
Is 53009 divisible by 3?
No. Its digits add up to 17, which is not a multiple of 3.
What is special about the number 53009?
It is a composite number with 8 divisors.