The number 52947
52947 is a composite number with 16 divisors. Its prime factorisation is × 37 × 53. Divisors (16): 1, 3, 9, 27, 37, 53, 111, 159, 333, 477, 999, 1431, 1961, 5883, 17649, 52947.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 52947: a Harshad number: divisible by its digit sum 27.
- 2
52947 is composite. Its prime factorisation is
- 3
The divisors add up to 82080; without 52947 itself that is 29133, so 52947 is deficient (29133 is less than 52947). Euler's totient φ(52947) = 33696 numbers up to 52947 share no factor with it.
- 4
The digits of 52947 add up to 27, and repeating that until one digit is left gives the digital root 9. The Collatz sequence (halve if even, else 3n+1) takes 140 steps to reach 1.
LaTeX source of the formulas on this page
\[ 52947 = 3^{3} \times 37 \times 53 \]52947 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 16 |
| Sum of divisors | 82080 |
| Euler totient φ(n) | 33696 |
| Square | 2803384809 |
| Cube | 148430815482123 |
| Square root | 230.102151 (= 3√5883) |
| Digit sum / digital root | 27 / 9 |
| Collatz steps to 1 | 140 |
| Scientific notation | 5.2947 × |
52947 in other forms
| Form | Value |
|---|---|
| In words | fifty-two thousand nine hundred and forty-seven |
| Binary (base 2) | 1100111011010011 |
| Octal (base 8) | 147323 |
| Hexadecimal (base 16) | CED3 |
| Base 3 | 2200122000 |
| As time | 52947 seconds = 14 h 42 min 27 s |
Is 52947 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | Yes (52947 ÷ 3 = 17649) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 3) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 2) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 3) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 6) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 3) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | Yes (52947 ÷ 9 = 5883) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 7) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 4) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 3) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 52947 a prime number?
No. 52947 = × 37 × 53, so it is divisible by 3.
What are the factors of 52947?
1, 3, 9, 27, 37, 53, 111, 159, 333, 477, 999, 1431, 1961, 5883, 17649, 52947.
What is 52947 in binary?
1100111011010011 (hexadecimal CED3, octal 147323).
What is the square root of 52947?
About 230.1022, exactly 3√5883.
Is 52947 divisible by 3?
Yes. Its digits add up to 27, a multiple of 3.
What is special about the number 52947?
52947 is a Harshad number: divisible by its digit sum 27.