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The number 52431

52431 is a composite number with 4 divisors. Its prime factorisation is 3 × 17477. Divisors (4): 1, 3, 17477, 52431.

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How to work it out

  1. 1

    What is special about 52431: a semiprime: 3 × 17477, the product of two primes.

  2. 2

    52431 is composite. Its prime factorisation is

    52431=3×1747752431 = 3 \times 17477
  3. 3

    The divisors add up to 69912; without 52431 itself that is 17481, so 52431 is deficient (17481 is less than 52431). Euler's totient φ(52431) = 34952 numbers up to 52431 share no factor with it.

  4. 4

    The digits of 52431 add up to 15, and repeating that until one digit is left gives the digital root 6. The Collatz sequence (halve if even, else 3n+1) takes 109 steps to reach 1.

LaTeX source of the formulas on this page
\[ 52431 = 3 \times 17477 \]

52431 at a glance

PropertyValue
Typecomposite
Number of divisors4
Sum of divisors69912
Euler totient φ(n)34952
Square2749009761
Cube144133330778991
Square root228.978165
Digit sum / digital root15 / 6
Collatz steps to 1109
Scientific notation5.2431 × 10410^{4}

52431 in other forms

FormValue
In wordsfifty-two thousand four hundred and thirty-one
Binary (base 2)1100110011001111
Octal (base 8)146317
Hexadecimal (base 16)CCCF
Base 32122220220
As time52431 seconds = 14 h 33 min 51 s

Is 52431 divisible by 2 to 12?

DivisorAnswerRule
2No (remainder 1)A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8).
3Yes (52431 ÷ 3 = 17477)A number is divisible by 3 if the digits add up to a multiple of 3.
4No (remainder 3)A number is divisible by 4 if the last two digits make a multiple of 4.
5No (remainder 1)A number is divisible by 5 if the last digit is 0 or 5.
6No (remainder 3)A number is divisible by 6 if it is divisible by both 2 and 3.
7No (remainder 1)A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7.
8No (remainder 7)A number is divisible by 8 if the last three digits make a multiple of 8.
9No (remainder 6)A number is divisible by 9 if the digits add up to a multiple of 9.
10No (remainder 1)A number is divisible by 10 if the last digit is 0.
11No (remainder 5)A number is divisible by 11 if the alternating sum of the digits is a multiple of 11.
12No (remainder 3)A number is divisible by 12 if it is divisible by both 3 and 4.

Questions

Is 52431 a prime number?

No. 52431 = 3 × 17477, so it is divisible by 3.

What are the factors of 52431?

1, 3, 17477, 52431.

What is 52431 in binary?

1100110011001111 (hexadecimal CCCF, octal 146317).

What is the square root of 52431?

About 228.9782.

Is 52431 divisible by 3?

Yes. Its digits add up to 15, a multiple of 3.

What is special about the number 52431?

52431 is a semiprime: 3 × 17477, the product of two primes.

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