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The number 52133

52133 is a composite number with 4 divisors. Its prime factorisation is 37 × 1409. Divisors (4): 1, 37, 1409, 52133.

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How to work it out

  1. 1

    What is special about 52133: a semiprime: 37 × 1409, the product of two primes.

  2. 2

    52133 is composite. Its prime factorisation is

    52133=37×140952133 = 37 \times 1409
  3. 3

    The divisors add up to 53580; without 52133 itself that is 1447, so 52133 is deficient (1447 is less than 52133). Euler's totient φ(52133) = 50688 numbers up to 52133 share no factor with it.

  4. 4

    The digits of 52133 add up to 14, and repeating that until one digit is left gives the digital root 5. The Collatz sequence (halve if even, else 3n+1) takes 158 steps to reach 1.

LaTeX source of the formulas on this page
\[ 52133 = 37 \times 1409 \]

52133 at a glance

PropertyValue
Typecomposite
Number of divisors4
Sum of divisors53580
Euler totient φ(n)50688
Square2717849689
Cube141689657836637
Square root228.326521
Digit sum / digital root14 / 5
Collatz steps to 1158
Scientific notation5.2133 × 10410^{4}

52133 in other forms

FormValue
In wordsfifty-two thousand one hundred and thirty-three
Binary (base 2)1100101110100101
Octal (base 8)145645
Hexadecimal (base 16)CBA5
Base 32122111212
As time52133 seconds = 14 h 28 min 53 s

Is 52133 divisible by 2 to 12?

DivisorAnswerRule
2No (remainder 1)A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8).
3No (remainder 2)A number is divisible by 3 if the digits add up to a multiple of 3.
4No (remainder 1)A number is divisible by 4 if the last two digits make a multiple of 4.
5No (remainder 3)A number is divisible by 5 if the last digit is 0 or 5.
6No (remainder 5)A number is divisible by 6 if it is divisible by both 2 and 3.
7No (remainder 4)A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7.
8No (remainder 5)A number is divisible by 8 if the last three digits make a multiple of 8.
9No (remainder 5)A number is divisible by 9 if the digits add up to a multiple of 9.
10No (remainder 3)A number is divisible by 10 if the last digit is 0.
11No (remainder 4)A number is divisible by 11 if the alternating sum of the digits is a multiple of 11.
12No (remainder 5)A number is divisible by 12 if it is divisible by both 3 and 4.

Questions

Is 52133 a prime number?

No. 52133 = 37 × 1409, so it is divisible by 37.

What are the factors of 52133?

1, 37, 1409, 52133.

What is 52133 in binary?

1100101110100101 (hexadecimal CBA5, octal 145645).

What is the square root of 52133?

About 228.3265.

Is 52133 divisible by 3?

No. Its digits add up to 14, which is not a multiple of 3.

What is special about the number 52133?

52133 is a semiprime: 37 × 1409, the product of two primes.

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