The number 52037
52037 is a composite number with 4 divisors. Its prime factorisation is 17 × 3061. Divisors (4): 1, 17, 3061, 52037.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 52037: a Harshad number: divisible by its digit sum 17; a semiprime: 17 × 3061, the product of two primes.
- 2
52037 is composite. Its prime factorisation is
- 3
The divisors add up to 55116; without 52037 itself that is 3079, so 52037 is deficient (3079 is less than 52037). Euler's totient φ(52037) = 48960 numbers up to 52037 share no factor with it.
- 4
The digits of 52037 add up to 17, and repeating that until one digit is left gives the digital root 8. The Collatz sequence (halve if even, else 3n+1) takes 140 steps to reach 1.
LaTeX source of the formulas on this page
\[ 52037 = 17 \times 3061 \]
52037 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 4 |
| Sum of divisors | 55116 |
| Euler totient φ(n) | 48960 |
| Square | 2707849369 |
| Cube | 140908357614653 |
| Square root | 228.116198 |
| Digit sum / digital root | 17 / 8 |
| Collatz steps to 1 | 140 |
| Scientific notation | 5.2037 × |
52037 in other forms
| Form | Value |
|---|---|
| In words | fifty-two thousand and thirty-seven |
| Binary (base 2) | 1100101101000101 |
| Octal (base 8) | 145505 |
| Hexadecimal (base 16) | CB45 |
| Base 3 | 2122101022 |
| As time | 52037 seconds = 14 h 27 min 17 s |
Is 52037 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 2) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 1) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 2) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 5) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 6) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 5) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 8) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 7) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 7) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 5) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 52037 a prime number?
No. 52037 = 17 × 3061, so it is divisible by 17.
What are the factors of 52037?
1, 17, 3061, 52037.
What is 52037 in binary?
1100101101000101 (hexadecimal CB45, octal 145505).
What is the square root of 52037?
About 228.1162.
Is 52037 divisible by 3?
No. Its digits add up to 17, which is not a multiple of 3.
What is special about the number 52037?
52037 is a Harshad number: divisible by its digit sum 17; a semiprime: 17 × 3061, the product of two primes.