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The number 51731

51731 is a composite number with 6 divisors. Its prime factorisation is 17217^{2} Ɨ 179. Divisors (6): 1, 17, 179, 289, 3043, 51731.

Number

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How to work it out

  1. 1

    What is special about 51731: a Harshad number: divisible by its digit sum 17.

  2. 2

    51731 is composite. Its prime factorisation is

    51731=172Ɨ17951731 = 17^{2} \times 179
  3. 3

    The divisors add up to 55260; without 51731 itself that is 3529, so 51731 is deficient (3529 is less than 51731). Euler's totient φ(51731) = 48416 numbers up to 51731 share no factor with it.

  4. 4

    The digits of 51731 add up to 17, and repeating that until one digit is left gives the digital root 8. The Collatz sequence (halve if even, else 3n+1) takes 83 steps to reach 1.

LaTeX source of the formulas on this page
\[ 51731 = 17^{2} \times 179 \]

51731 at a glance

PropertyValue
Typecomposite
Number of divisors6
Sum of divisors55260
Euler totient φ(n)48416
Square2676096361
Cube138437140850891
Square root227.444499 (= 17√179)
Digit sum / digital root17 / 8
Collatz steps to 183
Scientific notation5.1731 Ɨ 10410^{4}

51731 in other forms

FormValue
In wordsfifty-one thousand seven hundred and thirty-one
Binary (base 2)1100101000010011
Octal (base 8)145023
Hexadecimal (base 16)CA13
Base 32121221222
As time51731 seconds = 14 h 22 min 11 s

Is 51731 divisible by 2 to 12?

DivisorAnswerRule
2No (remainder 1)A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8).
3No (remainder 2)A number is divisible by 3 if the digits add up to a multiple of 3.
4No (remainder 3)A number is divisible by 4 if the last two digits make a multiple of 4.
5No (remainder 1)A number is divisible by 5 if the last digit is 0 or 5.
6No (remainder 5)A number is divisible by 6 if it is divisible by both 2 and 3.
7No (remainder 1)A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7.
8No (remainder 3)A number is divisible by 8 if the last three digits make a multiple of 8.
9No (remainder 8)A number is divisible by 9 if the digits add up to a multiple of 9.
10No (remainder 1)A number is divisible by 10 if the last digit is 0.
11No (remainder 9)A number is divisible by 11 if the alternating sum of the digits is a multiple of 11.
12No (remainder 11)A number is divisible by 12 if it is divisible by both 3 and 4.

Questions

Is 51731 a prime number?

No. 51731 = 17217^{2} Ɨ 179, so it is divisible by 17.

What are the factors of 51731?

1, 17, 179, 289, 3043, 51731.

What is 51731 in binary?

1100101000010011 (hexadecimal CA13, octal 145023).

What is the square root of 51731?

About 227.4445, exactly 17√179.

Is 51731 divisible by 3?

No. Its digits add up to 17, which is not a multiple of 3.

What is special about the number 51731?

51731 is a Harshad number: divisible by its digit sum 17.

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