The number 50983
50983 is a composite number with 4 divisors. Its prime factorisation is 17 × 2999. Divisors (4): 1, 17, 2999, 50983.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 50983: a semiprime: 17 × 2999, the product of two primes.
- 2
50983 is composite. Its prime factorisation is
- 3
The divisors add up to 54000; without 50983 itself that is 3017, so 50983 is deficient (3017 is less than 50983). Euler's totient φ(50983) = 47968 numbers up to 50983 share no factor with it.
- 4
The digits of 50983 add up to 25, and repeating that until one digit is left gives the digital root 7. The Collatz sequence (halve if even, else 3n+1) takes 109 steps to reach 1.
LaTeX source of the formulas on this page
\[ 50983 = 17 \times 2999 \]
50983 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 4 |
| Sum of divisors | 54000 |
| Euler totient φ(n) | 47968 |
| Square | 2599266289 |
| Cube | 132518393212087 |
| Square root | 225.794154 |
| Digit sum / digital root | 25 / 7 |
| Collatz steps to 1 | 109 |
| Scientific notation | 5.0983 × |
50983 in other forms
| Form | Value |
|---|---|
| In words | fifty thousand nine hundred and eighty-three |
| Binary (base 2) | 1100011100100111 |
| Octal (base 8) | 143447 |
| Hexadecimal (base 16) | C727 |
| Base 3 | 2120221021 |
| As time | 50983 seconds = 14 h 9 min 43 s |
Is 50983 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 1) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 3) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 3) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 1) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 2) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 7) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 7) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 3) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 9) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 7) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 50983 a prime number?
No. 50983 = 17 × 2999, so it is divisible by 17.
What are the factors of 50983?
1, 17, 2999, 50983.
What is 50983 in binary?
1100011100100111 (hexadecimal C727, octal 143447).
What is the square root of 50983?
About 225.7942.
Is 50983 divisible by 3?
No. Its digits add up to 25, which is not a multiple of 3.
What is special about the number 50983?
50983 is a semiprime: 17 × 2999, the product of two primes.