The number 49997
49997 is a composite number with 6 divisors. Its prime factorisation is Ć 173. Divisors (6): 1, 17, 173, 289, 2941, 49997.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
49997 has no famous special property in the usual lists (prime, square, cube, triangular, Fibonacci, palindrome, perfect), but it is still a composite number.
- 2
49997 is composite. Its prime factorisation is
- 3
The divisors add up to 53418; without 49997 itself that is 3421, so 49997 is deficient (3421 is less than 49997). Euler's totient Ļ(49997) = 46784 numbers up to 49997 share no factor with it.
- 4
The digits of 49997 add up to 38, and repeating that until one digit is left gives the digital root 2. The Collatz sequence (halve if even, else 3n+1) takes 158 steps to reach 1.
LaTeX source of the formulas on this page
\[ 49997 = 17^{2} \times 173 \]49997 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 6 |
| Sum of divisors | 53418 |
| Euler totient Ļ(n) | 46784 |
| Square | 2499700009 |
| Cube | 124977501349973 |
| Square root | 223.600089 (= 17ā173) |
| Digit sum / digital root | 38 / 2 |
| Collatz steps to 1 | 158 |
| Scientific notation | 4.9997 Ć |
49997 in other forms
| Form | Value |
|---|---|
| In words | forty-nine thousand nine hundred and ninety-seven |
| Binary (base 2) | 1100001101001101 |
| Octal (base 8) | 141515 |
| Hexadecimal (base 16) | C34D |
| Base 3 | 2112120202 |
| As time | 49997 seconds = 13 h 53 min 17 s |
Is 49997 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 2) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 1) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 2) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 5) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 3) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 5) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 2) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 7) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 2) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 5) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 49997 a prime number?
No. 49997 = Ć 173, so it is divisible by 17.
What are the factors of 49997?
1, 17, 173, 289, 2941, 49997.
What is 49997 in binary?
1100001101001101 (hexadecimal C34D, octal 141515).
What is the square root of 49997?
About 223.6001, exactly 17ā173.
Is 49997 divisible by 3?
No. Its digits add up to 38, which is not a multiple of 3.
What is special about the number 49997?
It is a composite number with 6 divisors.