The number 49909
49909 is a composite number with 4 divisors. Its prime factorisation is 29 × 1721. Divisors (4): 1, 29, 1721, 49909.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 49909: a semiprime: 29 × 1721, the product of two primes.
- 2
49909 is composite. Its prime factorisation is
- 3
The divisors add up to 51660; without 49909 itself that is 1751, so 49909 is deficient (1751 is less than 49909). Euler's totient φ(49909) = 48160 numbers up to 49909 share no factor with it.
- 4
The digits of 49909 add up to 31, and repeating that until one digit is left gives the digital root 4. The Collatz sequence (halve if even, else 3n+1) takes 52 steps to reach 1.
LaTeX source of the formulas on this page
\[ 49909 = 29 \times 1721 \]
49909 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 4 |
| Sum of divisors | 51660 |
| Euler totient φ(n) | 48160 |
| Square | 2490908281 |
| Cube | 124318741396429 |
| Square root | 223.403223 |
| Digit sum / digital root | 31 / 4 |
| Collatz steps to 1 | 52 |
| Scientific notation | 4.9909 × |
49909 in other forms
| Form | Value |
|---|---|
| In words | forty-nine thousand nine hundred and nine |
| Binary (base 2) | 1100001011110101 |
| Octal (base 8) | 141365 |
| Hexadecimal (base 16) | C2F5 |
| Base 3 | 2112110111 |
| As time | 49909 seconds = 13 h 51 min 49 s |
Is 49909 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 1) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 1) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 4) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 1) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 6) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 5) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 4) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 9) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 2) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 1) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 49909 a prime number?
No. 49909 = 29 × 1721, so it is divisible by 29.
What are the factors of 49909?
1, 29, 1721, 49909.
What is 49909 in binary?
1100001011110101 (hexadecimal C2F5, octal 141365).
What is the square root of 49909?
About 223.4032.
Is 49909 divisible by 3?
No. Its digits add up to 31, which is not a multiple of 3.
What is special about the number 49909?
49909 is a semiprime: 29 × 1721, the product of two primes.