The number 49813
49813 is a composite number with 4 divisors. Its prime factorisation is 109 × 457. Divisors (4): 1, 109, 457, 49813.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 49813: a semiprime: 109 × 457, the product of two primes.
- 2
49813 is composite. Its prime factorisation is
- 3
The divisors add up to 50380; without 49813 itself that is 567, so 49813 is deficient (567 is less than 49813). Euler's totient φ(49813) = 49248 numbers up to 49813 share no factor with it.
- 4
The digits of 49813 add up to 25, and repeating that until one digit is left gives the digital root 7. The Collatz sequence (halve if even, else 3n+1) takes 96 steps to reach 1.
LaTeX source of the formulas on this page
\[ 49813 = 109 \times 457 \]
49813 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 4 |
| Sum of divisors | 50380 |
| Euler totient φ(n) | 49248 |
| Square | 2481334969 |
| Cube | 123602738810797 |
| Square root | 223.188261 |
| Digit sum / digital root | 25 / 7 |
| Collatz steps to 1 | 96 |
| Scientific notation | 4.9813 × |
49813 in other forms
| Form | Value |
|---|---|
| In words | forty-nine thousand eight hundred and thirteen |
| Binary (base 2) | 1100001010010101 |
| Octal (base 8) | 141225 |
| Hexadecimal (base 16) | C295 |
| Base 3 | 2112022221 |
| As time | 49813 seconds = 13 h 50 min 13 s |
Is 49813 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 1) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 1) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 3) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 1) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 1) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 5) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 7) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 3) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 5) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 1) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 49813 a prime number?
No. 49813 = 109 × 457, so it is divisible by 109.
What are the factors of 49813?
1, 109, 457, 49813.
What is 49813 in binary?
1100001010010101 (hexadecimal C295, octal 141225).
What is the square root of 49813?
About 223.1883.
Is 49813 divisible by 3?
No. Its digits add up to 25, which is not a multiple of 3.
What is special about the number 49813?
49813 is a semiprime: 109 × 457, the product of two primes.