The number 49733
49733 is a composite number with 4 divisors. Its prime factorisation is 41 × 1213. Divisors (4): 1, 41, 1213, 49733.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 49733: a semiprime: 41 × 1213, the product of two primes.
- 2
49733 is composite. Its prime factorisation is
- 3
The divisors add up to 50988; without 49733 itself that is 1255, so 49733 is deficient (1255 is less than 49733). Euler's totient φ(49733) = 48480 numbers up to 49733 share no factor with it.
- 4
The digits of 49733 add up to 26, and repeating that until one digit is left gives the digital root 8. The Collatz sequence (halve if even, else 3n+1) takes 114 steps to reach 1.
LaTeX source of the formulas on this page
\[ 49733 = 41 \times 1213 \]
49733 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 4 |
| Sum of divisors | 50988 |
| Euler totient φ(n) | 48480 |
| Square | 2473371289 |
| Cube | 123008174315837 |
| Square root | 223.008968 |
| Digit sum / digital root | 26 / 8 |
| Collatz steps to 1 | 114 |
| Scientific notation | 4.9733 × |
49733 in other forms
| Form | Value |
|---|---|
| In words | forty-nine thousand seven hundred and thirty-three |
| Binary (base 2) | 1100001001000101 |
| Octal (base 8) | 141105 |
| Hexadecimal (base 16) | C245 |
| Base 3 | 2112012222 |
| As time | 49733 seconds = 13 h 48 min 53 s |
Is 49733 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 2) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 1) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 3) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 5) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 5) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 5) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 8) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 3) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 2) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 5) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 49733 a prime number?
No. 49733 = 41 × 1213, so it is divisible by 41.
What are the factors of 49733?
1, 41, 1213, 49733.
What is 49733 in binary?
1100001001000101 (hexadecimal C245, octal 141105).
What is the square root of 49733?
About 223.0090.
Is 49733 divisible by 3?
No. Its digits add up to 26, which is not a multiple of 3.
What is special about the number 49733?
49733 is a semiprime: 41 × 1213, the product of two primes.