The number 49133
49133 is a composite number with 4 divisors. Its prime factorisation is 7 × 7019. Divisors (4): 1, 7, 7019, 49133.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 49133: a semiprime: 7 × 7019, the product of two primes.
- 2
49133 is composite. Its prime factorisation is
- 3
The divisors add up to 56160; without 49133 itself that is 7027, so 49133 is deficient (7027 is less than 49133). Euler's totient φ(49133) = 42108 numbers up to 49133 share no factor with it.
- 4
The digits of 49133 add up to 20, and repeating that until one digit is left gives the digital root 2. The Collatz sequence (halve if even, else 3n+1) takes 70 steps to reach 1.
LaTeX source of the formulas on this page
\[ 49133 = 7 \times 7019 \]
49133 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 4 |
| Sum of divisors | 56160 |
| Euler totient φ(n) | 42108 |
| Square | 2414051689 |
| Cube | 118609601635637 |
| Square root | 221.659649 |
| Digit sum / digital root | 20 / 2 |
| Collatz steps to 1 | 70 |
| Scientific notation | 4.9133 × |
49133 in other forms
| Form | Value |
|---|---|
| In words | forty-nine thousand one hundred and thirty-three |
| Binary (base 2) | 1011111111101101 |
| Octal (base 8) | 137755 |
| Hexadecimal (base 16) | BFED |
| Base 3 | 2111101202 |
| As time | 49133 seconds = 13 h 38 min 53 s |
Is 49133 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 2) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 1) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 3) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 5) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | Yes (49133 ÷ 7 = 7019) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 5) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 2) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 3) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 7) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 5) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 49133 a prime number?
No. 49133 = 7 × 7019, so it is divisible by 7.
What are the factors of 49133?
1, 7, 7019, 49133.
What is 49133 in binary?
1011111111101101 (hexadecimal BFED, octal 137755).
What is the square root of 49133?
About 221.6596.
Is 49133 divisible by 3?
No. Its digits add up to 20, which is not a multiple of 3.
What is special about the number 49133?
49133 is a semiprime: 7 × 7019, the product of two primes.