The number 49129
49129 is a composite number with 4 divisors. Its prime factorisation is 73 × 673. Divisors (4): 1, 73, 673, 49129.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 49129: a semiprime: 73 × 673, the product of two primes.
- 2
49129 is composite. Its prime factorisation is
- 3
The divisors add up to 49876; without 49129 itself that is 747, so 49129 is deficient (747 is less than 49129). Euler's totient φ(49129) = 48384 numbers up to 49129 share no factor with it.
- 4
The digits of 49129 add up to 25, and repeating that until one digit is left gives the digital root 7. The Collatz sequence (halve if even, else 3n+1) takes 127 steps to reach 1.
LaTeX source of the formulas on this page
\[ 49129 = 73 \times 673 \]
49129 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 4 |
| Sum of divisors | 49876 |
| Euler totient φ(n) | 48384 |
| Square | 2413658641 |
| Cube | 118580635373689 |
| Square root | 221.650626 |
| Digit sum / digital root | 25 / 7 |
| Collatz steps to 1 | 127 |
| Scientific notation | 4.9129 × |
49129 in other forms
| Form | Value |
|---|---|
| In words | forty-nine thousand one hundred and twenty-nine |
| Binary (base 2) | 1011111111101001 |
| Octal (base 8) | 137751 |
| Hexadecimal (base 16) | BFE9 |
| Base 3 | 2111101121 |
| As time | 49129 seconds = 13 h 38 min 49 s |
Is 49129 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 1) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 1) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 4) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 1) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 3) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 1) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 7) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 9) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 3) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 1) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 49129 a prime number?
No. 49129 = 73 × 673, so it is divisible by 73.
What are the factors of 49129?
1, 73, 673, 49129.
What is 49129 in binary?
1011111111101001 (hexadecimal BFE9, octal 137751).
What is the square root of 49129?
About 221.6506.
Is 49129 divisible by 3?
No. Its digits add up to 25, which is not a multiple of 3.
What is special about the number 49129?
49129 is a semiprime: 73 × 673, the product of two primes.