The number 49109
49109 is the 5047th prime number. Its only divisors are 1 and 49109.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 49109: the 5047th prime number.
- 2
49109 is prime, so its only factors are 1 and 49109. It is the 5047th prime; the next prime is 49117 and the one before is 49103.
- 3
The divisors add up to 49110; without 49109 itself that is 1, so 49109 is deficient (1 is less than 49109). Euler's totient φ(49109) = 49108 numbers up to 49109 share no factor with it.
- 4
The digits of 49109 add up to 23, and repeating that until one digit is left gives the digital root 5. The Collatz sequence (halve if even, else 3n+1) takes 65 steps to reach 1.
49109 at a glance
| Property | Value |
|---|---|
| Type | prime |
| Number of divisors | 2 |
| Sum of divisors | 49110 |
| Euler totient φ(n) | 49108 |
| Square | 2411693881 |
| Cube | 118435874802029 |
| Square root | 221.605505 |
| Digit sum / digital root | 23 / 5 |
| Collatz steps to 1 | 65 |
| Scientific notation | 4.9109 × |
49109 in other forms
| Form | Value |
|---|---|
| In words | forty-nine thousand one hundred and nine |
| Binary (base 2) | 1011111111010101 |
| Octal (base 8) | 137725 |
| Hexadecimal (base 16) | BFD5 |
| Base 3 | 2111100212 |
| As time | 49109 seconds = 13 h 38 min 29 s |
Is 49109 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 2) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 1) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 4) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 5) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 4) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 5) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 5) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 9) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 5) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 5) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 49109 a prime number?
Yes. 49109 is divisible only by 1 and itself.
What are the factors of 49109?
1, 49109.
What is 49109 in binary?
1011111111010101 (hexadecimal BFD5, octal 137725).
What is the square root of 49109?
About 221.6055.
Is 49109 divisible by 3?
No. Its digits add up to 23, which is not a multiple of 3.
What is special about the number 49109?
49109 is the 5047th prime number.