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The number 48223

48223 is a composite number with 6 divisors. Its prime factorisation is 7 Ɨ 83283^{2}. Divisors (6): 1, 7, 83, 581, 6889, 48223.

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How to work it out

  1. 1

    What is special about 48223: a happy number: repeatedly adding the squares of its digits reaches 1.

  2. 2

    48223 is composite. Its prime factorisation is

    48223=7Ɨ83248223 = 7 \times 83^{2}
  3. 3

    The divisors add up to 55784; without 48223 itself that is 7561, so 48223 is deficient (7561 is less than 48223). Euler's totient φ(48223) = 40836 numbers up to 48223 share no factor with it.

  4. 4

    The digits of 48223 add up to 19, and repeating that until one digit is left gives the digital root 1. The Collatz sequence (halve if even, else 3n+1) takes 127 steps to reach 1.

LaTeX source of the formulas on this page
\[ 48223 = 7 \times 83^{2} \]

48223 at a glance

PropertyValue
Typecomposite
Number of divisors6
Sum of divisors55784
Euler totient φ(n)40836
Square2325457729
Cube112140548065567
Square root219.597359 (= 83√7)
Digit sum / digital root19 / 1
Collatz steps to 1127
Scientific notation4.8223 Ɨ 10410^{4}

48223 in other forms

FormValue
In wordsforty-eight thousand two hundred and twenty-three
Binary (base 2)1011110001011111
Octal (base 8)136137
Hexadecimal (base 16)BC5F
Base 32110011001
As time48223 seconds = 13 h 23 min 43 s

Is 48223 divisible by 2 to 12?

DivisorAnswerRule
2No (remainder 1)A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8).
3No (remainder 1)A number is divisible by 3 if the digits add up to a multiple of 3.
4No (remainder 3)A number is divisible by 4 if the last two digits make a multiple of 4.
5No (remainder 3)A number is divisible by 5 if the last digit is 0 or 5.
6No (remainder 1)A number is divisible by 6 if it is divisible by both 2 and 3.
7Yes (48223 Ć· 7 = 6889)A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7.
8No (remainder 7)A number is divisible by 8 if the last three digits make a multiple of 8.
9No (remainder 1)A number is divisible by 9 if the digits add up to a multiple of 9.
10No (remainder 3)A number is divisible by 10 if the last digit is 0.
11No (remainder 10)A number is divisible by 11 if the alternating sum of the digits is a multiple of 11.
12No (remainder 7)A number is divisible by 12 if it is divisible by both 3 and 4.

Questions

Is 48223 a prime number?

No. 48223 = 7 Ɨ 83283^{2}, so it is divisible by 7.

What are the factors of 48223?

1, 7, 83, 581, 6889, 48223.

What is 48223 in binary?

1011110001011111 (hexadecimal BC5F, octal 136137).

What is the square root of 48223?

About 219.5974, exactly 83√7.

Is 48223 divisible by 3?

No. Its digits add up to 19, which is not a multiple of 3.

What is special about the number 48223?

48223 is a happy number: repeatedly adding the squares of its digits reaches 1.

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    48223: is it prime? Factors, square root, binary, Roman numeral | WordGPT