The number 47908
47908 is a composite number with 24 divisors. Its prime factorisation is × 7 × 29 × 59. Divisors (24): 1, 2, 4, 7, 14, 28, 29, 58, 59, 116, 118, 203, 236, 406, 413, 812 … 47908.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 47908: a Harshad number: divisible by its digit sum 28.
- 2
47908 is composite. Its prime factorisation is
- 3
The divisors add up to 100800; without 47908 itself that is 52892, so 47908 is abundant (52892 is more than 47908). Euler's totient φ(47908) = 19488 numbers up to 47908 share no factor with it.
- 4
The digits of 47908 add up to 28, and repeating that until one digit is left gives the digital root 1. The Collatz sequence (halve if even, else 3n+1) takes 189 steps to reach 1.
LaTeX source of the formulas on this page
\[ 47908 = 2^{2} \times 7 \times 29 \times 59 \]47908 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 24 |
| Sum of divisors | 100800 |
| Euler totient φ(n) | 19488 |
| Square | 2295176464 |
| Cube | 109957314037312 |
| Square root | 218.878962 (= 2√11977) |
| Digit sum / digital root | 28 / 1 |
| Collatz steps to 1 | 189 |
| Scientific notation | 4.7908 × |
47908 in other forms
| Form | Value |
|---|---|
| In words | forty-seven thousand nine hundred and eight |
| Binary (base 2) | 1011101100100100 |
| Octal (base 8) | 135444 |
| Hexadecimal (base 16) | BB24 |
| Base 3 | 2102201101 |
| As time | 47908 seconds = 13 h 18 min 28 s |
Is 47908 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | Yes (47908 ÷ 2 = 23954) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 1) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | Yes (47908 ÷ 4 = 11977) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 3) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 4) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | Yes (47908 ÷ 7 = 6844) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 4) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 1) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 8) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 3) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 4) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 47908 a prime number?
No. 47908 = × 7 × 29 × 59, so it is divisible by 2.
What are the factors of 47908?
1, 2, 4, 7, 14, 28, 29, 58, 59, 116, 118, 203, 236, 406, 413, 812, 826, 1652, 1711, 3422, 6844, 11977, 23954, 47908.
What is 47908 in binary?
1011101100100100 (hexadecimal BB24, octal 135444).
What is the square root of 47908?
About 218.8790, exactly 2√11977.
Is 47908 divisible by 3?
No. Its digits add up to 28, which is not a multiple of 3.
What is special about the number 47908?
47908 is a Harshad number: divisible by its digit sum 28.