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The number 47483

47483 is a composite number with 4 divisors. Its prime factorisation is 103 × 461. Divisors (4): 1, 103, 461, 47483.

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How to work it out

  1. 1

    What is special about 47483: a semiprime: 103 × 461, the product of two primes.

  2. 2

    47483 is composite. Its prime factorisation is

    47483=103×46147483 = 103 \times 461
  3. 3

    The divisors add up to 48048; without 47483 itself that is 565, so 47483 is deficient (565 is less than 47483). Euler's totient φ(47483) = 46920 numbers up to 47483 share no factor with it.

  4. 4

    The digits of 47483 add up to 26, and repeating that until one digit is left gives the digital root 8. The Collatz sequence (halve if even, else 3n+1) takes 75 steps to reach 1.

LaTeX source of the formulas on this page
\[ 47483 = 103 \times 461 \]

47483 at a glance

PropertyValue
Typecomposite
Number of divisors4
Sum of divisors48048
Euler totient φ(n)46920
Square2254635289
Cube107056847427587
Square root217.905943
Digit sum / digital root26 / 8
Collatz steps to 175
Scientific notation4.7483 × 10410^{4}

47483 in other forms

FormValue
In wordsforty-seven thousand four hundred and eighty-three
Binary (base 2)1011100101111011
Octal (base 8)134573
Hexadecimal (base 16)B97B
Base 32102010122
As time47483 seconds = 13 h 11 min 23 s

Is 47483 divisible by 2 to 12?

DivisorAnswerRule
2No (remainder 1)A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8).
3No (remainder 2)A number is divisible by 3 if the digits add up to a multiple of 3.
4No (remainder 3)A number is divisible by 4 if the last two digits make a multiple of 4.
5No (remainder 3)A number is divisible by 5 if the last digit is 0 or 5.
6No (remainder 5)A number is divisible by 6 if it is divisible by both 2 and 3.
7No (remainder 2)A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7.
8No (remainder 3)A number is divisible by 8 if the last three digits make a multiple of 8.
9No (remainder 8)A number is divisible by 9 if the digits add up to a multiple of 9.
10No (remainder 3)A number is divisible by 10 if the last digit is 0.
11No (remainder 7)A number is divisible by 11 if the alternating sum of the digits is a multiple of 11.
12No (remainder 11)A number is divisible by 12 if it is divisible by both 3 and 4.

Questions

Is 47483 a prime number?

No. 47483 = 103 × 461, so it is divisible by 103.

What are the factors of 47483?

1, 103, 461, 47483.

What is 47483 in binary?

1011100101111011 (hexadecimal B97B, octal 134573).

What is the square root of 47483?

About 217.9059.

Is 47483 divisible by 3?

No. Its digits add up to 26, which is not a multiple of 3.

What is special about the number 47483?

47483 is a semiprime: 103 × 461, the product of two primes.

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