The number 43423
43423 is a composite number with 4 divisors. Its prime factorisation is 173 × 251. Divisors (4): 1, 173, 251, 43423.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 43423: a semiprime: 173 × 251, the product of two primes.
- 2
43423 is composite. Its prime factorisation is
- 3
The divisors add up to 43848; without 43423 itself that is 425, so 43423 is deficient (425 is less than 43423). Euler's totient φ(43423) = 43000 numbers up to 43423 share no factor with it.
- 4
The digits of 43423 add up to 16, and repeating that until one digit is left gives the digital root 7. The Collatz sequence (halve if even, else 3n+1) takes 207 steps to reach 1.
LaTeX source of the formulas on this page
\[ 43423 = 173 \times 251 \]
43423 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 4 |
| Sum of divisors | 43848 |
| Euler totient φ(n) | 43000 |
| Square | 1885556929 |
| Cube | 81876538527967 |
| Square root | 208.381861 |
| Digit sum / digital root | 16 / 7 |
| Collatz steps to 1 | 207 |
| Scientific notation | 4.3423 × |
43423 in other forms
| Form | Value |
|---|---|
| In words | forty-three thousand four hundred and twenty-three |
| Binary (base 2) | 1010100110011111 |
| Octal (base 8) | 124637 |
| Hexadecimal (base 16) | A99F |
| Base 3 | 2012120021 |
| As time | 43423 seconds = 12 h 3 min 43 s |
Is 43423 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 1) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 3) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 3) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 1) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 2) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 7) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 7) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 3) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 6) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 7) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 43423 a prime number?
No. 43423 = 173 × 251, so it is divisible by 173.
What are the factors of 43423?
1, 173, 251, 43423.
What is 43423 in binary?
1010100110011111 (hexadecimal A99F, octal 124637).
What is the square root of 43423?
About 208.3819.
Is 43423 divisible by 3?
No. Its digits add up to 16, which is not a multiple of 3.
What is special about the number 43423?
43423 is a semiprime: 173 × 251, the product of two primes.