The number 43231
43231 is a composite number with 4 divisors. Its prime factorisation is 17 × 2543. Divisors (4): 1, 17, 2543, 43231.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 43231: a semiprime: 17 × 2543, the product of two primes.
- 2
43231 is composite. Its prime factorisation is
- 3
The divisors add up to 45792; without 43231 itself that is 2561, so 43231 is deficient (2561 is less than 43231). Euler's totient φ(43231) = 40672 numbers up to 43231 share no factor with it.
- 4
The digits of 43231 add up to 13, and repeating that until one digit is left gives the digital root 4. The Collatz sequence (halve if even, else 3n+1) takes 163 steps to reach 1.
LaTeX source of the formulas on this page
\[ 43231 = 17 \times 2543 \]
43231 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 4 |
| Sum of divisors | 45792 |
| Euler totient φ(n) | 40672 |
| Square | 1868919361 |
| Cube | 80795252895391 |
| Square root | 207.920658 |
| Digit sum / digital root | 13 / 4 |
| Collatz steps to 1 | 163 |
| Scientific notation | 4.3231 × |
43231 in other forms
| Form | Value |
|---|---|
| In words | forty-three thousand two hundred and thirty-one |
| Binary (base 2) | 1010100011011111 |
| Octal (base 8) | 124337 |
| Hexadecimal (base 16) | A8DF |
| Base 3 | 2012022011 |
| As time | 43231 seconds = 12 h 0 min 31 s |
Is 43231 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 1) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 3) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 1) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 1) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 6) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 7) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 4) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 1) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 1) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 7) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 43231 a prime number?
No. 43231 = 17 × 2543, so it is divisible by 17.
What are the factors of 43231?
1, 17, 2543, 43231.
What is 43231 in binary?
1010100011011111 (hexadecimal A8DF, octal 124337).
What is the square root of 43231?
About 207.9207.
Is 43231 divisible by 3?
No. Its digits add up to 13, which is not a multiple of 3.
What is special about the number 43231?
43231 is a semiprime: 17 × 2543, the product of two primes.