The number 42935
42935 is a composite number with 8 divisors. Its prime factorisation is 5 × 31 × 277. Divisors (8): 1, 5, 31, 155, 277, 1385, 8587, 42935.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
42935 has no famous special property in the usual lists (prime, square, cube, triangular, Fibonacci, palindrome, perfect), but it is still a composite number.
- 2
42935 is composite. Its prime factorisation is
- 3
The divisors add up to 53376; without 42935 itself that is 10441, so 42935 is deficient (10441 is less than 42935). Euler's totient φ(42935) = 33120 numbers up to 42935 share no factor with it.
- 4
The digits of 42935 add up to 23, and repeating that until one digit is left gives the digital root 5. The Collatz sequence (halve if even, else 3n+1) takes 49 steps to reach 1.
LaTeX source of the formulas on this page
\[ 42935 = 5 \times 31 \times 277 \]
42935 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 8 |
| Sum of divisors | 53376 |
| Euler totient φ(n) | 33120 |
| Square | 1843414225 |
| Cube | 79146989750375 |
| Square root | 207.207625 |
| Digit sum / digital root | 23 / 5 |
| Collatz steps to 1 | 49 |
| Scientific notation | 4.2935 × |
42935 in other forms
| Form | Value |
|---|---|
| In words | forty-two thousand nine hundred and thirty-five |
| Binary (base 2) | 1010011110110111 |
| Octal (base 8) | 123667 |
| Hexadecimal (base 16) | A7B7 |
| Base 3 | 2011220012 |
| As time | 42935 seconds = 11 h 55 min 35 s |
Is 42935 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 2) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 3) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | Yes (42935 ÷ 5 = 8587) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 5) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 4) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 7) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 5) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 5) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 2) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 11) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 42935 a prime number?
No. 42935 = 5 × 31 × 277, so it is divisible by 5.
What are the factors of 42935?
1, 5, 31, 155, 277, 1385, 8587, 42935.
What is 42935 in binary?
1010011110110111 (hexadecimal A7B7, octal 123667).
What is the square root of 42935?
About 207.2076.
Is 42935 divisible by 3?
No. Its digits add up to 23, which is not a multiple of 3.
What is special about the number 42935?
It is a composite number with 8 divisors.